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alekssr [168]
3 years ago
13

Fe3O4(s) + 4H2(g)3Fe(s) + 4H2O(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings w

hen 1.79 moles of Fe3O4(s) react at standard conditions. S°surroundings = J/K
Chemistry
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

dS= 1.79*169.504

j/k = 303.41 j/k

Explanation:

Fe3O4(s) + 4H2(g) --> 3Fe (s)+ 4H2O(g)

dS(Fe3O4) =146.4 j/k

dS(H2) =130.684

dS(Fe) =27.78

dS(H2O) =188.825

dSrxn = dS[product]-dS[reactants]

= 3*dS(Fe)+ 4*dS(H2O)-[1*dS(Fe3O4)+ 4dS(H2)]

= [3*27.78 +4*188.825-146.4 -4*130.684] j/k = 169.504 j/k

This is the dS for 1mole Fe3O4

for 1.79 mols Fe3O4

dS= 1.79*169.504 j/k = 303.41 j/k

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2 years ago
How many formula units make up 36.0 g of magnesium chloride (MgCl2)?
zalisa [80]

Answer: There are 2.29\times 10^{23} formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles

1 mole of MgCl_2 contains = 6.023\times 10^{23} formula units

Thus 0.38 moles of MgCl_2 contains = \frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23} formula units

Thus there are 2.29\times 10^{23} formula units

6 0
3 years ago
Select all that apply.
yuradex [85]

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1;2;3

Explanation:

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8 0
3 years ago
Does iron melt at 1728 degrees Celsius
erastovalidia [21]
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4 0
3 years ago
Read 2 more answers
For 2Na (s) + Cl2(g) - 2NaCI (s) ,how many grams of sodium Chloride will be made from 115 g of sodium metal when reacted with ex
Solnce55 [7]

<u>Given:</u>

Mass of Na = 115 g

Excess Cl2

<u>To determine:</u>

Mass of NaCl produced

<u>Explanation:</u>

Given reaction is-

2Na(s) + Cl2(g) → 2NaCl(s)

Since Cl2 is in excess, Na will be the limiting reagent

As per the reaction stoichiometry Na:NaCl = 1:1

i.e. moles of Na reacted = moles of NaCl formed

Now, # moles of Na = mass of Na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

Therefore, moles of NaCl = 5

Molar mass of NaCl = 58 g/mol

Mass of NaCl = 5 moles * 58 g.mol-1 = 290 g

Ans: Amount of Nacl produced = 290 g

5 0
2 years ago
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