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Dominik [7]
3 years ago
12

In a lab, silver nitrate,AgNO₃, is dissolved in water until no solid is observed in the container. Then, a solution of sodium ch

loride, NaCl, is added to the container. When you combine these aqueous solutions, there is no noticeable change in temperature; however, a solid precipitates and there is a slight change of color. Which statements about the lab experiment involving silver nitrate and a sodium chloride solution are true?
a. Formation of a solid indicates that a chemical reaction occurred

b. The initial disappearance of silver nitrate in water indicates a chemical reaction occurred

c. The color change of the solution indicates a chemical reaction occurred

d. A chemical reaction occurred when silver nitrate was added to water

e. A chemical reaction occurred when the solutions were combined

f. The lack of temperature change indicates a chemical reaction didn't occur
Chemistry
1 answer:
leva [86]3 years ago
6 0

Answer:

The answer to your question is: A, C, E

Explanation:

After reading the information given, we can conclude that both reactants react to form a new solid product and another product that do not precipitate.

The reaction is:

                         AgNO₃ + NaCl   ⇒      AgCl  +  NaNO₃

a. Formation of a solid indicates that a chemical reaction occurred  This option is correct, precipitation indicates that a changed occurred in the solution due to a chemical reaction.

b. The initial disappearance of silver nitrate in water indicates a chemical reaction occurred  No, what is happing is that silver nitrate is dissolving in water, this process is a physical change because matter do not change its nature.

c. The color change of the solution indicates a chemical reaction occurred  This option is true, when a color appears suggest the formation of a new product.

d. A chemical reaction occurred when silver nitrate was added to water

This option is not correct, in this process silver nitrate is dissolving in water but it is not a chemical reaction because matter does not change is nature.

e. A chemical reaction occurred when the solutions were combined  This option is true because silver nitrate and sodium chloride react to form a new product (solid formation and change in color).

f. The lack of temperature change indicates a chemical reaction didn't occur This is false, some reactions do not need a change of color to happen.

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Which model of the atom is thought to be true?
FinnZ [79.3K]

Answer:

Hi the answer should be B or 2

Explanation:

Hope this helps!

6 0
2 years ago
Question 15 (1 point)
Digiron [165]

Answer:

Atoms are electrically neutral because the number of protons, which carry a 1+ charge, in the nucleus of an atom is equal to the number of electrons, which carry a 1- charge, in the atom. The result is that the total positive charge of the protons cancels out the total negative charge of the electrons so that the net charge of the atom is zero. Most atoms, however, can either gain or lose electrons; when they do so, the number of electrons becomes different from the number of protons in the nucleus. The resulting charged species is called an ion.

Cations and anions

When a neutral atom loses one or more electrons, the total number of electrons decreases while the number of protons in the nucleus remains the same. The result is that the atom becomes a cation—an ion with a net positive charge.

The opposite process can also occur. When a neutral atom gains one or more electrons, the number of electrons increases while the number of protons in the nucleus remains the same. The result is that the atom becomes an anion—an ion with a net negative charge. We can illustrate this by examining some very simple cations and anions, those formed when a single hydrogen atom loses or gains an electron.

Note: Hydrogen is actually somewhat unusual in that it readily forms both cations and anions. Most elements much prefer to form only one or the other. In terms of its electron configuration, can you explain why hydrogen can form both cations and anions? Feel free to post in the comments at the end of the article!

A hydrogen cation, a hydrogen atom, and a hydrogen anion.

A hydrogen cation, a hydrogen atom, and a hydrogen anion.

Classification cation neutral atom anion

No. of protons 111 111 111

No. of electrons 000 111 222

Net charge 111++plus 000 111-−minus

If a neutral hydrogen atom ( \text{H}Hstart text, H, end text, center) loses an electron, it becomes a hydrogen cation ( \text{H}^+H  

+

start text, H, end text, start superscript, plus, end superscript, left). Conversely, if the neutral \text{H}Hstart text, H, end text atom gains an electron, it becomes a hydrogen anion ( \text{H}^-H  

−

start text, H, end text, start superscript, minus, end superscript, right), also known as a hydride ion. Image credit: adapted from Boundless Learning, CC BY-SA 4.0.

In the center column, we have a diagram of a single, neutral hydrogen atom. It contains one proton and one electron; thus, its net charge is zero. If hydrogen loses its electron, it forms the cation \text{H}^+H  

+

start text, H, end text, start superscript, plus, end superscript (left column). The \text{H}^+H  

+

start text, H, end text, start superscript, plus, end superscript cation has a net charge of 1+ from the one proton in the nucleus since there are no electrons to cancel out the positive charge. If neutral hydrogen gains an electron, it forms the anion \text{H}^-H  

−

start text, H, end text, start superscript, minus, end superscript (right column). The \text{H}^-H  

−

start text, H, end text, start superscript, minus, end superscript anion has a net charge of 1- because it has one extra electron compared to the total number of protons.

Explanation: Hopes this gives a better explanation on them!

6 0
3 years ago
The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihyd
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Answer:

The answer is "= 0.078 \ kg \ H_2".

Explanation:

calculating the moles in CH_4 =\frac{PV}{RT}

                                                =\frac{(0.58 \ atm) \times (923 \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(232^{\circ} C +273)}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (0.0821 \frac{L \cdot atm}{K \cdot mol})(505)K}\\\\=\frac{(535.34 \ atm \cdot \ L) }{ (41.4605 \frac{L \cdot atm}{mol})}\\\\= 12.9 \ mol

Eqution:

CH_4 +H_2O \to  3H_2+ CO \ (g)

Calculating the amount of H_2 produced:

= 12.9 \ mol CH_4 \times  \frac{3 \ mol \ H_2 }{1 \ mol \ CH_4}\times \frac{2.016 g H_2}{1 \ mol \ H_2}\\\\= 78 \ g \ H_2 \\\\= 0.078 \ kg \ H_2

So, the amount of dihydrogen produced = 0.078 \frac{kg}{s}

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<span>mass He = 13.0 mol x 4.00 g/mol = 52.0 g</span>
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