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lakkis [162]
3 years ago
9

The atomic mass of an element depends upon the _____.

Chemistry
2 answers:
qwelly [4]3 years ago
8 0

Answer: mass and relative abundance of each isotope of that element

Explanation:-

For example:

If an element X has two isotopes with following masses ad abundance:

Mass of isotope 1 = 267.8 amu

% abundance of isotope 1 = 87.8% = 0.878

Mass of isotope 2 = 269.9 amu

% abundance of isotope 2 = 12.2% = 0.122

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

\text{ Average atomic mass of an element X}=\sum[(267.8\times 0.878)+(269.9\times 0.122)]

\text{ Average atomic mass of an element X}=268.06amu

xxMikexx [17]3 years ago
3 0
<h3>The atomic mass of an element depends upon the mass and relative abundance of each isotope of that element</h3><h3>Further explanation</h3>

Atoms of the same element do not always have the same mass called Isotopes

Atoms in nature have different masses, so the atomic mass is calculated based on the average mass of all atoms in nature. So that the isotopes of some of these atoms, atomic mass is the average mass of all isotopes in nature

\large {\boxed {\bold{mass ~ average ~ atom ~ X ~ = ~ \frac {mass ~ isotope ~ 1 + mass ~ isotope ~ 2} {total ~ whole ~ atom ~ X}}}

In determining atomic mass, the standard is the mass of 1 carbon-12 atom whose mass is 1 amu (amu = atomic mass unit)

So the obtained atomic mass is the atomic mass relative to the carbon-12 atom

\large {\boxed {\bold{ ~ atomic\:mass\:X = \frac {mass ~ average ~ 1 ~ atom ~ X} {\frac {1} {12}. mass ~ 1 ~ atom ~ C-12}}}

  • Example

Isotope Cl-35 75.53%, 34.969 amu

Isotope Cl-37 24.47%, 36.966 amu

\displaystyle Relative\:atomic\:mass\:Cl=\frac {(75,53.34,969)+(24,47.36,966)} {100}

Average atomic mass Cl = 35.45 amu

So atomic mass of Cl is:

\large {Ar ~ Cl ~ = ~ \dfrac {mass ~ average ~ 1 ~ atom ~ Cl} {\frac {1} {12}. mass ~ 1 ~ atom ~ C-12}}

\large {Ar ~ Cl ~ = ~ \dfrac {35,45 ~ amu} {\frac {1} {12}. 12 ~ amu}}

So atomic mass Cl = 35.45

Whereas the Atomic Number (Z) shows the number of protons in an atomic nucleus from an element. If the atom is neutral then the number of protons will equal the number of electrons. So the atomic number can also indicate the number of electrons.

So atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Mass Number (A) = Number of protons + Number of Neutrons

So there is a difference between the mass number and atomic mass

<h3>Learn more   </h3>

The subatomic particle that has the least mass  

brainly.com/question/2224691  

element 2512X  

brainly.com/question/2572495  

about subatomic particles statement  

brainly.com/question/3176193  

Keywords: mass number, atomic mass, amu, isotope  

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Ganezh [65]

Answer:

All of the above.

Explanation:

Hello there!

In this case, according to the definition of the Lewis structures, which are represented by the valence electrons, we first identify that the N atom has five valence electrons and each fluorine has seven valence electrons.

In such a way, we cans say that N is the central atom due to its lower electronegativity, the molecule has 7+7+7+5=26 valence electrons and the three F-N bonds are covalent, therefore the answer is all of the above.

Regards!

7 0
3 years ago
H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.20 moles
abruzzese [7]

<u>Answer:</u> The value of \Delta S^o for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

H_2(g)+F_2(g)\rightarrow 2HF(g)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]

We are given:

\Delta S^o_{(HF(g))}=173.78J/K.mol\\\Delta S^o_{(H_2)}=130.68J/K.mol\\\Delta S^o_{(F_2)}=202.78J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K

Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K

We are given:

Moles of hydrogen gas reacted = 2.20 moles

By Stoichiometry of the reaction:

When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K

So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = \frac{-14.1}{1}\times 2.20=-31.02J/K

Hence, the value of \Delta S^o for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

7 0
3 years ago
Which of the following is true of group 6A?
USPshnik [31]

Answer:

The answer to your question is: Includes sulfur and gain two electrons

Explanation:

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Gain 2 electrons . This option is true, Elements in group VI have six valence electrons so they gain to electrons to become estable.

Tend to form +2 ions  This option is wrong, this elements form -2 ions

Have 5 valence electrons This option is wrong, this elements have 6 valence electrons.

7 0
3 years ago
Which equation shows how to calculate how many grams (g) of KCL would be produced from 4 mol KOH the balanced reaction is mgcl2
Tresset [83]
First of all, we need tô calculate moles of KCl
next, mass=mol×molar mass

8 0
4 years ago
Read 2 more answers
What is the name of the compound with the chemical formula ScBO3
NARA [144]

Explanation:

Scandium Borate ScBO3 Molecular Weight -

6 0
3 years ago
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