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2 years ago

Please helpppppp I be thankful

Chemistry

1 answer:

grigory [225]2 years ago

8 0

Valence électrons don’t define which group You are in so you can cross those choices out.
A would be incorrect because element 1 has 1 valence electron while element 2 has 2 valence electrons.
D would be correct because both elements have two valence electrons.
Also, pls don’t hate if I am wrong!

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A certain element forms an ion with 36 electrons and a charge of +2. identify the element. express your answer as a chemical sym

blsea [12.9K]

The element is Sr (strontium)

strontium is in atomic number 38 in the periodic table. Strontium has 2.8.8.8.8.2

it loses two electrons to become stable hence it has a charge of 2+. when strontium loses two electron it form ion with 36 electrons

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3 years ago

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nadya68 [22]

11.7 g hope this helps and have a great day

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1 year ago

0.000431 L<br><br> Express your answer as an integer.

Molodets [167]

A whole number, not a fraction, that can be negative, positive or zero are integers. They cannot have decimal places.

Now, converting 0.000431 L to decimal an integer as:

$0.000431 L = 431\times 10^{-6} L$

Since, $1 L = 10^{6} \mu L$

So, $431\times 10^{-6} L\times \frac{10^{6 \mu L}}{1 L} = 431 \mu L$ .

Hence, the integer value for 0.000431 L is $431 \mu L[$ .

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3 years ago

Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO

vlada-n [284]

Answer:

$2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}$

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

$2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}$

Best regards!

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2 years ago

6. What does the symbol AH stand for?

Vesnalui [34]

the heat of reaction for a chemical reaction

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3 years ago