8.345 lbs
The density of water at 4 degrees Celsius is 8.345 lbs/U.S. gal. Multiply the specific gravity of any solid or liquid by this number to get the density in pounds per U.S. gallon.
Answer:
(a) The molality of this solution is 0.0613
(b)The molality of this solution is 2.04
Explanation:
The molality (m) of a solution is defined as the number of moles of solute present per kg of solvent.
The Molality of a solution is determined by the expression:
Molality is expressed in units
(a) You have 14.3 g of sucrose (C₁₂H₂₂O₁₁), the solute. With the molar mass of sucrose being 342 , then 14.3 grams of the compound represents the following number of moles:
0.042 moles
Having 685 g= 0.685 kg (being 1000 g= 1 kg) of water, the solvent, molality can be calculated as:
Solving:
molality= 0.0613
<u><em>The molality of this solution is 0.0613</em></u><u><em></em></u>
(b) In this case you have 7.15 moles of ethylene glycol (C₂H₆O₂), the solute, in 3505 g (equal to 3.505 kg) of water, the solvent, molality can be calculated as:
Solving:
molality= 2.04
<em><u>The molality of this solution is 2.04</u></em><em><u /></em>
I think you are suposse to use coefficients of products and reactents to balance the number of atoms of an element on both sides of a chemical equation
i hope this helps
The answer is common table salt. Looking at the chemical make up, putting an acid (I think chlorine) and and base (probably sodium) makes water (H20) and salt. So you answer would be salt
<span>Oxidation is the loss of electrons and corresponds to an increase in oxidation state. A reduction is the gain of electrons and corresponds to a decrease in oxidation state. Balancing redox reactions can be more complicated than balancing other types of reactions because both the mass and charge must be balanced. Redox reactions occurring in aqueous solutions can be balanced by using a special procedure called the half-reaction method of balancing. In this procedure, the overall equation is broken down into two half-reactions: one for oxidation and the other for reduction. The half-reactions are balanced individually and then added together so that the number of electrons generated in the oxidation half-reaction is the same as the number of electrons consumed in the reduction half-reaction.</span>