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dalvyx [7]
3 years ago
15

A house is maintained at 1 atm and 24°C. Outdoor air at 5.5°C infiltrates into the house through the cracks and warm air inside

the house is forced to leave the house at a rate of 90 m3 /hr. The gas constant of air is R = 0.287 kPa·m3 /kg·K. The constant pressure specific heat of air at room temperature is cp = 1.005 kJ/kg:°C.
a. Create a schematic representation of the system, indicating all the mass and energy interactions across the boundary.
b. Determine the mass flow rate of the warm air exiting the house (in kg/s).
c. Determine the mass flow rate of the cold air entering the house (in kg/s).
d. Determine the rate of net energy loss of the house due to mass transfer (in kW).
e. List the assumptions and approximations that were needed to solve this problem.
Physics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

5454gjb

Explanation:

512212njun][[]

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15 to who helps me out!
s2008m [1.1K]

Answer:

a. same

b. less

c. same

d. same?

Explanation:

the mass will always be the same no matter where it is. the weight however depends on the gravity.

7 0
3 years ago
Describe the relationship of attractive forces between molecules
Ede4ka [16]
<span>Describe the relationship of attractive forces between molecules and the ability of a solvent to dissolve a substance. Solvents can dissolve a substance only if the attraction of the solvent molecules is greater than the attraction between the molecules of the substance.</span>
4 0
3 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A pipe closed at both ends can have standing wav
uranmaximum [27]

Answer:

68.8 Hz

137.6 Hz, 206.4 Hz

Explanation:

L = Length of tube = 2.5 m

v = Velocity of sound in air = 344 m/s

Distance between nodes is given by

L=\dfrac{\lambda}{2}+m\dfrac{\lambda}{2}\\\Rightarrow \dfrac{\lambda(n+1)}{2}=L\\\Rightarrow \lambda=\dfrac{2L}{n+1}

Where n = 0, 1, 2, 3, ...

Making n+1 = n

\lambda=\dfrac{2L}{n}

where n = 1, 2, 3 .....

For fundamental frequency n = 1

\lambda=\dfrac{2\times 2.5}{1}\\\Rightarrow \lambda=5\ m

Frequency is given by

f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{344}{5}\\\Rightarrow f=68.8\ Hz

The fundamental frequency is 68.8 Hz

First overtone

2f=2\times 68.8=137.6\ Hz

Second overtone

3f=3\times 68.8=206.4\ Hz

The overtones are 137.6 Hz, 206.4 Hz

4 0
3 years ago
In general, sound<br> travels faster through
BartSMP [9]

Answer:

solids

Explanation:

5 0
3 years ago
A 1-kilogram ball has a kinetic energy of 50 joules the speed of the ball is
sveta [45]

Answer:

10 m/s

Explanation:

3 0
3 years ago
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