Spectator ion are ions which remain unchanged during chemical equation and does not affect equilibrium
chemical equation for the reaction is as follows
NaSO4 +Babr2 ---> 2 Nabr + BaSO4
ionic equation is as follows
Ba ^+2 + SO^-2 --->BaSO4(s)
therefore the spectator ion are Na+ and Br- ions
CU is the element symbol for Copper.
Answer:
The pH of the buffer is 3.54.
Explanation:
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
![pH=pK_a+\log(\frac{[salt]}{[acid]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%29)
![pH=pK_a+\log(\frac{[NaHCO_3]}{[H_2CO_3]})](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%28%5Cfrac%7B%5BNaHCO_3%5D%7D%7B%5BH_2CO_3%5D%7D%29)
We are given:
= negative logarithm of acid dissociation constant of carbonic acid
![pK_a=-\log[K_a]=-\[1.8\times 10^{-5}]=4.74](https://tex.z-dn.net/?f=pK_a%3D-%5Clog%5BK_a%5D%3D-%5C%5B1.8%5Ctimes%2010%5E%7B-5%7D%5D%3D4.74)
![[NaC_2H_3O_2]=0.059 M](https://tex.z-dn.net/?f=%5BNaC_2H_3O_2%5D%3D0.059%20M)
![[HC_2H_3O_2]=0.94 M](https://tex.z-dn.net/?f=%5BHC_2H_3O_2%5D%3D0.94%20M)
pH = ?
Putting values in above equation, we get:
The pH of the buffer is 3.54.
