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Shalnov [3]
3 years ago
5

How many moles is 0.025 g of NaCO3? (Show Your Work)

Chemistry
1 answer:
poizon [28]3 years ago
4 0

mol of Na2CO3 = 2.36 x 10⁻⁴

<h3>Further explanation</h3>

Given

Mass : 0.025 g of Na2CO3

Required

moles

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass  :

mol = mass : molar mass

mass = mol x molar mass

Input the value :

mol = mass : MW Na2CO3

mol = 0.025 g : 106 g/mol

mol = 2.36 x 10⁻⁴

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Answer:

C.

Explanation:

\frac{1x10}x^{-14} = 1x10^{-9} \\ x =1x10^{-5} \\\\[OH][H]= 1x10^{-14}

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Calculate the number of hydrogen atoms in 33.0 g CH4
Elena-2011 [213]

Answer:

The number of hydrogen atoms is 4.96x10²⁴.

 

Explanation:

The number of atoms can be found with the following equation:

n = N*\eta_{H}

Where:

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First, we need to find the number of hydrogen moles. The number of moles of CH₄ is:

\eta_{CH_{4}} = \frac{m}{M}

Where:

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\eta_{CH_{4}} = \frac{33 g}{16.04 g/mol} = 2.06 mol

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Hence, the number of hydrogen atoms is:

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I hope it helps you!      

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If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent Bond

                

                Between 0.4 and 1.7 then it is Polar Covalent Bond

            

                Greater than 1.7 then it is Ionic

 

For Br₂;

                    E.N of Bromine      =   2.96

                    E.N of Bromine      =   2.96

                                                   ________

                    E.N Difference             0.00          (Non Polar Covalent Bond)


For MgS;

                    E.N of Sulfur               =   2.58

                    E.N of Magnesium      =   1.31

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For SO₂;

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                                                   ________

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For KF;

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