1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Shalnov [3]
2 years ago
5

How many moles is 0.025 g of NaCO3? (Show Your Work)

Chemistry
1 answer:
poizon [28]2 years ago
4 0

mol of Na2CO3 = 2.36 x 10⁻⁴

<h3>Further explanation</h3>

Given

Mass : 0.025 g of Na2CO3

Required

moles

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass  :

mol = mass : molar mass

mass = mol x molar mass

Input the value :

mol = mass : MW Na2CO3

mol = 0.025 g : 106 g/mol

mol = 2.36 x 10⁻⁴

You might be interested in
copper hydroxide and potassium sulfate are produced when potassium hydroxide reacts with copper sulfate balanced equation
a_sh-v [17]

This problem is requiring the balanced chemical equation that takes place when copper hydroxide and potassium sulfate are produced when reacting potassium hydroxide with copper sulfate.

<h3>Balancing chemical equations:</h3>

In chemistry, balancing chemical equations is based on the law of conservation of mass, which demands us to have equal number of atoms on both sides of the chemical equation. This can be accomplished by inserting coefficients in front of the chemical species.

For this particular case, we have potassium hydroxide with copper sulfate on the reactants side, however, copper can be copper (I) or copper (II) as it has 1+ and 2+ as its possible oxidation numbers. In addition, copper hydroxide and potassium sulfate as the products. Hence, we can assume this is all about copper (II) so we can write:

KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

As we can see, potassium, hydrogen and oxygen have two atoms each on the products side, but just one on the reactants side; drawback we can overcome by putting a 2 in front of KOH so as to balance it:

2KOH+CuSO_4\rightarrow K_2SO_4+Cu(OH)_2

Learn more about balancing chemical equations: brainly.com/question/8062886

8 0
2 years ago
How many moles of oxygen are produced when 29.2 g of water is decomposed according to H20 H2 + O2​
Katarina [22]

8.1moles

Explanation:

Given parameters:

Mass of water to be decomposed = 29.2g

Unknown:

Number of moles of oxygen.

Solution:

To solve this problem, we first write the balanced reaction equation :

               2H₂O    →     2H₂    +    O₂

Now convert the given mass of the water to number of moles;

  Number of moles of water = \frac{mass}{molar mass}

 

  Molar mass of water = 2(1) + 16 = 18g/mol

  Number of moles of water = \frac{29.2}{18}  = 16.2moles

   From the balanced reaction equation:

   2 moles of water produced 1 mole of oxygen gas;

   16.2 mole of water will produce   \frac{16.2}{2}  = 8.1moles of oxygen gas

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

5 0
3 years ago
Determine how many moles of CO2 are required to produce 11.0 mol of glucose,
drek231 [11]

Answer:

Determine how many moles of CO2 are required to produce 11.0 mol of glucose,

i need points thanks for CO2moles

7 0
2 years ago
What volume, in mL, of carbon dioxide gas is produced at STP by the decomposition of 0.242 g calcium carbonate (the products are
damaskus [11]

Answer:

54.21 mL.

Explanation:

We'll begin by calculating the number of mole in 0.242 g calcium carbonate, CaCO3.

This is illustrated below:

Mass of CaCO3 = 0.242 g

Molar mass of CaCO3 = 40 + 12 +(16x3) = 40+ 12 + 48 = 100 g/mol

Mole of CaCO3 =?

Mole = mass /Molar mass

Mole of CaCO3 = 0.242/100

Mole of CaCO3 = 2.42×10¯³ mole.

Next, we shall write the balanced equation for the reaction. This is given below:

CaCO3 —> CaO + CO2

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole CaO and 1 mole of CO2.

Next, we shall determine the number of mole of CO2 produced from the reaction.

This can be obtained as follow:

From the balanced equation above,

1 mole of CaCO3 decomposed to produce 1 mole of CO2.

Therefore,

2.42×10¯³ mole of CaCO3 will also decompose to produce 2.42×10¯³ mole of CO2.

Therefore, 2.42×10¯³ mole of CO2 were obtained from the reaction.

Finally, we shall determine volume occupied by 2.42×10¯³ mole of CO2.

This can be obtained as follow:

1 mole of CO2 occupies 22400 mL at STP.

Therefore, 2.42×10¯³ mole of CO2 will occupy = 2.42×10¯³ x 22400 = 54.21 mL

Therefore, 54.21 mL of CO2 were obtained from the reaction.

7 0
2 years ago
The Same force is applied to a 300 kg go kart and 100 kg wagon at the beginning of the race. Which time is true about their acce
murzikaleks [220]

Answer: Well!

Explanation: I was going to answer D but fverdell82156 got to it first! So I have to agree with him! It is D!

3 0
2 years ago
Other questions:
  • Solids have:<br> fixed shape<br> O A and B<br> fixed size<br> neither A nor B
    9·1 answer
  • How does a photocopier use static electricity?
    10·2 answers
  • The solubility of O2 in water is 0.590 g/L at an oxygen pressure of around 15.5 atm. What is the Henry's law constant for O2?
    6·1 answer
  • Each hydrogen atom contains ___ protons.
    7·2 answers
  • Solution of Na2SO4 is <br> A) acidic B) basic C neutral
    14·1 answer
  • Choose the substance with the higher entropy in each pair. Assume constant temperature, except in part (5)
    13·1 answer
  • How do unbalanced forces cause a change in speed, direction, and position of an object?
    7·2 answers
  • The sequence was already outlined, so she didn't have to make any difficult choices
    10·1 answer
  • Consider a hypothetical gas which has the following Van der Waals constants:
    11·2 answers
  • 3. If you want to produce 12.6 g of HCl, how many grams of PCls will you need?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!