All categories

3 years ago

What is the relationship between frequency and wavelength?

Physics

1 answer:

mash [69]3 years ago

6 0

Answer:

Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength. For this reason, the wavelength ratio is the inverse of the frequency ratio.

Explanation:

none

You might be interested in

At the 1 s mark, which objects have equal momentum?

Rudik [331]

C. The bowling ball and the bicycle

p = mv
P of bike = 12x5 = 60
P of rock = 2x20 = 40
P of ball = 5 x 10 = 60

3 0

3 years ago

According to the reading, which of the following is NOT an obstacle to using big data for analysis and decision making? O Poor r

RoseWind [281]

Answer:

B .Limited types of data Insufficient data

Explanation:

To analyse and making decision from big data we have following thing

- Sufficient data

- data analyst

- Accurate data

- data Privacy

- data storage

So, limited data or data that cannot be copied is not and obstacle in data handling. hence option B Limited types of data Insufficient data is correct.

3 0

3 years ago

The electric field strength 5.0 cm from a very long charged wire is 3300 N/C .What is the electric field strength 10.0 cm from t

pogonyaev

To solve this problem we will apply the concepts related to the electric field. The relationship between state two and state 1 will be carried out on said electric field, and from there we will proceed to replace.

The electric field due to a wire a distance $r_1$ is,

$E_1 = \frac{\lambda}{2\pi \epsilon_0 r_1}$

The electric field due to a wire a distance $r_2$ is,

$E_2 = \frac{\lambda}{2\pi \epsilon_0 r_2}$

The ratio is

$\frac{E_2}{E_1} = \frac{\frac{\lambda}{2\pi \epsilon_0 r_2}}{\frac{\lambda}{2\pi \epsilon_0 r_1}}$

The electric field strength is,

$E_2 = E_1 (\frac{\frac{\lambda}{2\pi \epsilon_0 r_2}}{\frac{\lambda}{2\pi \epsilon_0 r_1}})$

$E_2 = E_1 (\frac{r_1}{r_2})$

$E_2 = (3300N/C)(\frac{5cm}{10cm})$

$E_2 = 1650N/C$

Therefore the electric field strenth 10cm from the wire is 1650N/C

5 0

3 years ago

A chef fills a 50 mL container with 43.5 of cooking oil. What is the density of the oil?

charle [14.2K]

$density= \frac{mass}{Volume} \\ d= \frac{m}{V} \\ d= \frac{43.5}{50} \\ d=0.87 \frac{u}{mL}$

"u" stands for "units" since the unit for mass in this problem is unknown.

8 0

3 years ago

A horse canters away from its trainer in a straight line, moving 37 m away in 9.1 s. It then turns abruptly and gallops halfway

vesna_86 [32]

Answer:

Average velocity = 1.69 m/s

Average speed = 5.09 m/s

Explanation:

Given that

Horse cover 37 m in 9.1 sec and 18.5 m in 1.8 sec.

As we know that

Average velocity = Displacement / Total time

Average speed = Total distance / Total time

Average velocity:

Average velocity = Displacement / Total time

Total displacement = 37 - 18.5 = 18.5 m

Total time = 9.1 + 1.8 =10.9 s

Average velocity = Displacement / Total time

Average velocity = 18.5 / 10.9

Average velocity = 1.69 m/s

Average speed:

Average speed = Total distance/ Total time

Total distance = 37 + 18.5 = 55.5 m

Total time = 9.1 + 1.8 =10.9 s

Average speed = Total distance/ Total time

Average speed = 55.5 / 10.9

Average speed = 5.09 m/s

3 0

3 years ago