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qaws [65]
3 years ago
7

What is the relationship between frequency and wavelength?

Physics
1 answer:
mash [69]3 years ago
6 0

Answer:

Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength. For this reason, the wavelength ratio is the inverse of the frequency ratio.

Explanation:

none

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Reactants → products
Nat2105 [25]
The answer is A

Explanation: the conservation of matter means that the mass stays the same
4 0
3 years ago
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A person jogs eight complete laps around a quarter-mile track in a total time of 12.5 min. Calculate (a) the average speed and (
Margarita [4]

\large\displaystyle\text{$\begin{gathered}\sf \huge \bf{\underline{Data:}} \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf 1\ mile = 1609.34 \ m \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf  1/4 \ mile = 402.33 \ m \end{gathered}$}

                           \large\displaystyle\text{$\begin{gathered}\sf 12.5 \not{min}*\frac{60 \ s}{1\not{min}}=750 \ s \end{gathered}$}

                   \large\displaystyle\text{$\begin{gathered}\sf \bf{A) \ Calculate \ the \ average \ speed: } \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf 402.33 \ m*8 \ laps = 3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf d=3218.64 \ m \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

                         \large\displaystyle\text{$\begin{gathered}\sf V=\frac{d}{t} \ \ \ \ \ \  V= \frac{3218.64 \ m }{750 \ s} \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V=4.29 \ m/s \end{gathered}$}

                  \large\displaystyle\text{$\begin{gathered}\sf \bf{B) \ Calculate \ the \ average \ speed \  in \ m/s} \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=402.33 \ m \end{gathered}$}  

                          \large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}

                          \large\displaystyle\text{$\begin{gathered}\sf V=\frac{D}{T} \ \ \ \ \ V=\frac{402.33 \ m}{750 \ s}   \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V= 0.53 \ m/s \end{gathered}$}

4 0
2 years ago
If a force of 26 N is applied to an object with a mass of 8 kg, the object will accelerate at m/s2
malfutka [58]
False, the numbers do not add up
8 0
3 years ago
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what is the pressure on a circular helipad of diameter 100 m on which a helicopter of weight 40,000 N is landing. *
Luba_88 [7]

Answer:

5.09 Pa

Explanation:

Area of the circle = πr²

The diameter is given, so 100/2 = 50 m is the radius.

π x 50² = 7854 m²

Pressure = force/area

Pressure = 40000/7854

Pressure = 5.09 Pa

Hope this helps!

4 0
3 years ago
A solid steel column is 4.0 m long and 0.20 m in diameter. Young's modulus for this steel is 2.0 × 1011 N/m2. By what distance d
zzz [600]

Answer:

3.12 x 10^-5 m

Explanation:

Length of steel column, L = 4 m

diameter, d = 0.2 m

radius = half of diameter = 0.1 m

Young's modulus, Y = 2 x 10^11 N/m^2

Mass of truck, m = 5000 kg

Force, F = mass of truck x acceleration due to gravity

F = 5000 x 9.8 = 49000 N

Area of crossection of cable,

A =  \pi r^{2}=3.14\times\0.1\times0.1=0.0314m^{2}

Let ΔL be the shrink in length of cable, then by the formula of Young's modulus

Y=\frac{F\times L}{A\times\Delta L}

\Delta L = \frac{F\times L}{A\times Y}

\Delta L = \frac{49000\times 4}{0.0314\times 2\times10^{11}}

ΔL = 3.12 x 10^-5 m

Thus, the shrink in the length of cable is 3.12 x 10^-5 m.

8 0
3 years ago
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