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ryzh [129]
3 years ago
14

Help!!Help!!Help!!Help!!

Physics
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:

y=8

Explanation:

every time you multiply x by 3 you divide y by 3.

x=2, multiply it by 3: x=6

y=24, divide it by 3: y=8

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A negative slope on the velocity vs. time graph indicates that the object is not
Svetlanka [38]

Answer: False, I think

Explanation:

Well it depends. Its hard to say without a function of the graph. Given a velocity graph, the first derivative is the acceleration.

Negative slope on a velocity graph means you are going in the negative direction. And over time, your velocity per unit of time is also decreasing. That means we are accelerating in the negative direction

4 0
3 years ago
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A radiographer stands six feet from the x-ray source when performing a portable chest exam and receives an exposure of 2 mGy. If
telo118 [61]

Answer:

  I₂ = 8 mG

Explanation:

The intensity of a beam is

          I = P / A

Where P is the emitted power which is 3) 3

           

Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft

          I₁ A₁  = I₂  A₂

           I₂ = I₁ A₁ / A₂

The area of ​​the beam if we assume that it is distributed either in the form of a sphere is

           A₁ = 4π r²

We substitute

            I₂ = I₁ (r₁ / r₂)²

           I₂ = 2 (6/3)²

           I₂ = 2 4

           I₂ = 8 mG

3 0
3 years ago
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_______is the product of a force and the time during which the force acts
saul85 [17]

Answer:

impulse is the product of a force and the time during which the force acts

Explanation:

i hope this will help you :)

7 0
3 years ago
A truck tire rotates at an initial angular speed of 21.5 rad/s. The driver steadily accelerates, and after 3.50 s the tire's ang
erma4kov [3.2K]

Given:

initial angular speed, \omega _{i} = 21.5 rad/s

final angular speed, \omega _{f} = 28.0 rad/s

time, t = 3.50 s

Solution:

Angular acceleration can be defined as the time rate of change of angular velocity and is given by:

\alpha = \frac{\omega_{f} - \omega _{i}}{t}

Now, putting the given values in the above formula:

\alpha = \frac{28.0 - 21.5}{3.50}

\alpha = 1.86 m/s^{2}

Therefore, angular acceleration is:

\alpha = 1.86 m/s^{2}

5 0
3 years ago
The mechanical advantage of a machine is always greater than 1. true or false
Alja [10]
True mechanical advantage of a machine is always greater than
6 0
3 years ago
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