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Olenka [21]
3 years ago
14

Dan confirms the authenticity of an amethyst stone by a few tests. During one of the tests, he finds the angle of the refracted

ray of light coming out of the amethyst into the air as 28°. If the refractive index of amethyst is 1.55, what is the incident angle?
Physics
2 answers:
PilotLPTM [1.2K]3 years ago
7 0
Snell's law.
n_{1}*sin  \alpha _{1}= n_{2}*sin  \alpha _{2}
1=incident
2=refracted
Since it's coming out of the amethyst into air:
n1=1.55
n2=1.0003
sin  \alpha _{2} = sin28°

Substituting back into Snell's equation we get sin  \alpha _{1}=0.303 so the angle is \alpha _{1}=arcsin0.303=17.6°
ololo11 [35]3 years ago
6 0

The answer is 47° I'm 100% positive

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