A three-carbon alkene contains two double bonds. Predict its molecular formula? A) C3H4 B) C3H5 C) C3H6
2 answers:
Answer:
A) C3H4
Explanation:
We have to remember that for each c<u>arbon we must have 4 bonds</u>. In a three-carbon alkene we will have 2 bonds for the <u>left carbon</u>, 4 bonds for the<u> central carbon</u> and 2 bonds for the <u>right carbon</u> (Figure 1). Therefore we have to add <u>2 hydrogens in the left carbon and 2 hydrogens for the right carbon</u>. Finally, if we count the number of carbons and hydrogens we will get C3H4.
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Answer:
Please see attachment
Explanation:
Please see attachment
Answer : The fugacity in the solution is, 16 bar.
Explanation : Given,
Fugacity of a pure component = 40 bar
Mole fraction of component = 0.4
Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.
Now we have to calculate the fugacity in the solution.
Formula used :
where,
= fugacity in the solution
= fugacity of a pure component
= mole fraction of component
Now put all the give values in the above formula, we get:
Therefore, the fugacity in the solution is, 16 bar.