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Sveta_85 [38]
3 years ago
11

A three-carbon alkene contains two double bonds. Predict its molecular formula? A) C3H4 B) C3H5 C) C3H6

Chemistry
2 answers:
Vilka [71]3 years ago
6 0

Answer:

A) C3H4

Explanation:

We have to remember that for each c<u>arbon we must have 4 bonds</u>. In a three-carbon alkene we will have 2 bonds for the <u>left carbon</u>, 4 bonds for the<u> central carbon</u> and 2 bonds for the <u>right carbon</u> (Figure 1). Therefore we have to add <u>2 hydrogens in the left carbon and 2 hydrogens for the right carbon</u>. Finally, if we count the number of carbons and hydrogens we will get C3H4.

anyanavicka [17]3 years ago
5 0
A three-carbon alkene contains two double bonds. My prediction of its molecular formula is A. C3H4.
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7 0
3 years ago
How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *
densk [106]

Answer:

26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃

Explanation:

To determine the number of moles of O₂ that are needed to react completely with 35.0 mol of FeCl₃, it is possible to use the reaction stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction),  and rule of three as follows: if 4 moles of FeCl₃ react with 3 moles of O₂, 35 moles of FeCl₃ with how many moles of O₂ will it react?

molesofO_{2} =\frac{35 moles of FeCl_{3}*3 moles of O_{2}  }{4 moles of FeCl_{3}}

moles of O₂= 26.25 ≅ 26.3

<u><em>26.3 moles of O₂ are needed to react completely with 35.0 mol of FeCl₃</em></u>

7 0
2 years ago
Gravitational Potential Energy is created when an object’s what changes
alisha [4.7K]

Answer:

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5 0
2 years ago
The mass percent of solute in a solution containing 3.73 g KBr dissolved in 131 g of H2O is:
Elina [12.6K]

\huge \underbrace \mathfrak \red{Answer}

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Explanation:

mass of solute(KBr) = 3.73g

mass of solvent(H2O) = 131g

mass of solution = mass of solute + mass of solvent

= 3.73 + 131

= 134.73g

\sf \large {mass \: percentage =  \frac{mass \: of \: solute}{mass \: of \: solvent}  \times 100} \\  \\  \sf  mass \: percentage =  \frac{3.73}{134.73}  \times 100 \\  \\  \sf mass \: percentage =  0.028 \times 100 \\  \\  \sf mass \: percentage = 28\%

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2 years ago
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2 years ago
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