The picture is pretty blurry, and some of the words are hard to make out.
In picture-D, Polaris is at the observer's zenith ... Straight up over his head. This is a dead giveaway all by itself, and you don't really need to know anything about the sun.
The observer is at the North Pole.
(90 degrees north latitude)
The sun is rising ... he hasn't seen it at all for the past 6 months, and he is freezing his GPS off.
Answer:
a) t = 0.75 s, b) t = 2.25 s
Explanation:
The speed of sound is constant in a material medium
v = 340 m / s
we can use the relations of uniform motion to find the time
v = x / t
t = x / v
In the exercise, the observer's distance to the wall is indicated d = 510 m, it also indicates that the shot is fired at the midpoint
x = d / 2
a) direct sound the distance from the observer to the screen is
x = 510/2 = 255 m
t = 255/340
t = 0.75 s
b) echo sound.
In this case the sound reaches the wall bounces, the distance is
x = d / 2 + d
x = 3/2 d
x = 3/2 510
x = 765 m
the time is
t = x / v
t = 765/340
t = 2.25 s
KE=1/2mv^2
KE=1/2(620.0)(9.00)^2
KE=25,110J
it's C
Answer:
the distance traveled by Charlotte in feet is 338.44 ft
Explanation:
Given;
speed of Charlotte, u = 66.5 mi/h
time of motion, t = 3.47 s
The distance traveled by Charlotte in feet is calculated as;
Therefore, the distance traveled by Charlotte in feet is 338.44 ft
Answer:
The independent variable is plotted on the x-axis. This is the variable that is being manipulated or controlled.