A spherical bowling ball with mass m = 4.1 kg and radius R = 0.117 m is thrown down the lane with an initial speed of v = 8.9 m/
s. The coefficient of kinetic friction between the sliding ball and the ground is ? = 0.25. Once the ball begins to roll without slipping it moves with a constant velocity down the lane.
1.What is the magnitude of the angular acceleration of the bowling ball as it slides down the lane?
2.What is magnitude of the linear acceleration of the bowling ball as it slides down the lane?
3.How long does it take the bowling ball to begin rolling without slipping?
4.How far does the bowling ball slide before it begins to roll without slipping?
1.What is the magnitude of the angular acceleration of the bowling ball as it slides down the lane?
2.What is magnitude of the linear acceleration of the bowling ball as it slides down the lane?
3.How long does it take the bowling ball to begin rolling without slipping?
4.How far does the bowling ball slide before it begins to roll without slipping?
1 answer:
Answer:Given mass = 4.1kg
Radius = 0.0117m
Velocity V = 8.4m/s
Coefficient of friction = 0.25
Explanation: Below is an attached solution to the problem stated above.
1. The angular acceleration is equal to 524rad/s^2
2. The linear acceleration is equal to 2.45m/s^2
3.the time it takes the ball to begin rolling = 0.98s
4. The distance the ball slides before it begins to roll = 7.05m
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Answer with Step-by -step explanation:
We are given that
b.
below the positive x-axis
Therefore, the angle made by vector A in counter clockwise direction when measure from positive x-axis=
x-component of vector A=
y-Component of vector A=
Magnitude of vector B=86 m
The vector B makes angle with positive x- axis=
x-component of vector B=
y-Component of vector B=
Vector A=
Vector B=
Vector C=A+B
Substitute the values
c.Direction=
The direction of the vector C=21.5 degree
