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2 years ago

What is the electron (subshell) configurations for 15P

Chemistry

2 answers:

prisoha [69]2 years ago

6 0

58 ce is the correct answer!

Stella [2.4K]2 years ago

5 0

15p: 1s2 2s2 2p6 3s2 3p3

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A 25.00-mL aliquot of a nitric acid solution of unknown concentration is pipetted into a 125-mL Erlenmeyer flask and 2 drops of

Semenov [28]

Answer:

0.0611M of HNO3

Explanation:

The concentration of the NaOH solution must be 0.1198M

The reaction of NaOH with HNO3 is:

NaOH + HNO3 → NaNO3 + H2O

1 mole of NaOH reacts per mole of HNO3.

That means the moles of NaOH used in the titration are equal to moles of HNO3.

Moles HNO3:

12.75mL = 0.01275L * (0.1198mol / L) = 0.0015274 moles NaOH = Moles HNO3.

In 25.00mL = 0.025L -The volume of the aliquot-:

0.00153 moles HNO3 / 0.025L =

7 0

3 years ago

A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the

alexdok [17]

Answer : The volume of the bubble is, 625 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 2.4 atm

$P_2$ = final pressure of gas = 1.0 atm

$V_1$ = initial volume of gas = 250 mL

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $15^oC=273+15=288K$

$T_2$ = final temperature of gas = $27^oC=273+27=300K$

Now put all the given values in the above equation, we get:

$\frac{2.4atm\times 250mL}{288K}=\frac{1.0atm\times V_2}{300K}$

$V_2=625mL$

Therefore, the volume of the bubble is, 625 mL

7 0

2 years ago

I have two solutions. In the first solution, 1.0 moles of sodium chloride is dissolved to make 1.0 liters of solution. In the se

charle [14.2K]

i not sure but I think yes

6 0

2 years ago

Identify the ways that art and science are similar

Katarina [22]

Answer:

Arts and science are similar in that they are expressions of what it is to be human in this world.

Explanation:

Both are driven by curiosity, discovery, the aspiration for knowledge of the world or oneself, and perhaps, as the conceptual artist Goshka Macuga said on her recent visit to Cern, a desire for world domination.

3 0

3 years ago

Read 2 more answers

using the equation, c5h12 8o2 arrow 5co2 6h2o, if 108 g of water are produced, how many grams of oxygen were consumed?

vfiekz [6]

Molar mass:

H₂O = 18.0 g/mol

O₂ = 32.0 g/mol

C₅H₁₂ + 8 O₂ -> 5 CO₂ + 6 H₂O

8 x (32 g ) ------------ 6 x (18 g )
mass O₂ ------------ 108 g H₂O

mass O₂ = 108 x 8 x 32 / 6 x 18

mass O₂ = 27648 / 108

mass O₂ = 256 g

hope this helps!

8 0

2 years ago