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3 years ago

An airplane cabin is pressurized to 570 mmhg. what is the pressure inside the cabin in atmospheres?

2 answers:

8 0

1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
$1 atm: 760 mmHg = x: 570 mmHg$
and from this, we find
$x= \frac{1 atm \cdot 570 mmHg}{760 mmHg} =0.75 atm$

OLEGan [10]3 years ago

7 0

Answer:

0.75 atmospheric pressure

Explanation:

Pressure, P = 570 mm of Hg

We know that 1 atmospheric pressure = 760 mm of Hg

So, 760 mm of Hg pressure = 1 atmospheric pressure

1 mm of Hg = 1 / 760 atm pressure

570 mm of Hg = 570 / 760 atm

= 0.75 atm

Thus, 570 mm of Hg pressure is equal to 0.75 atmospheric pressure.

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Give two ways of reversing the direction of the forces on the coil in the electric motor?

nikklg [1K]

Answer:

Interchanging the poles of the magnet

Reversing the direction of the applied current

Explanation:

The working of the electric motor is associated with Fleming's left-hand rule.
It states that if a current-carrying conductor is placed inside a magnetic field, it experiences a force in the direction perpendicular to the direction of the electric current and magnetic field.
These three physical quantities are placed in a mutually perpendicular direction.
So, in order to reverse the direction of force, you have to either change the direction of the current or magnetic field.

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3 years ago

What is the answer for number 10

Finger [1]

The vertical component is = vsinx m/s

If you know the angle, substitute the value of x.

If you know the velocity at which it is moving, substitute it for v

Hope it helps :)

3 0

3 years ago

A uniform marble rolls down a symmetrical bowl, start- ing from rest at the top of the left side. The top of each side is a dist

Paha777 [63]

Answer:

Part a)

$h' = \frac{10}{14} h$

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

$h' = \frac{10}{14} h$

so on smooth it will go to lower height

Explanation:

As we know by energy conservation the total energy at the bottom of the bowl is given as

$\frac{1}{2} mv^2 + \frac{1}{2}I\omega^2 = mgh$

here we know that on the left side the ball is rolling due to which it is having rotational and transnational both kinetic energy

now on the right side of the bowl there is no friction

so its rotational kinetic energy will not change and remains the same

so it will have

$\frac{1}{2}mv^2 = mgh'$

now we know that

$I = \frac{2}{5}mr^2$

$\omega = \frac{v}{r}$

so we have

$\frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = mgh$

$\frac{1}{2}mv^2 + \frac{1}{5}mv^2 = mgh$

$\frac{7}{10}mv^2 = mgh$

$\frac{1}{2}mv^2 = \frac{10}{14}mgh$

so the height on the smooth side is given as

$h' = \frac{10}{14} h$

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

$h' = \frac{10}{14} h$

so on smooth it will go to lower height

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4 years ago

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For numbers 2 and 3, which one is compression and which one is rarefaction?

DENIUS [597]

Compression is above the equilibrium and rarefaction is below

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4 years ago

A 6 kg weight is lifted off the ground to a height that gives it 70.56 j of gravitational potential energy. what is its height?

Marina CMI [18]

GPE= 70.56 J -------------------> GPE= mgh-------------> X= height
70.56 = 6(kg) * 9.8(m/s/s) * X
70.56 = 58.8X
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X= 1.2
The height is 1.2 feet or meters (whatever unit you are using in this problem)

5 0

3 years ago

Read 2 more answers