Given data: <span>molar mass = 180.2 g/mol in 920.0 ml of water at 25 °c.
</span><span>the vapor pressure of pure water at 25 °c is 23.76 mm hg.
</span>Asked: <span>the vapor pressure of a solution made by dissolving 109 grams of glucose
</span><span>
Solution:
moles glucose = 109 g/ 180.2 g/mol=0.605
mass water = 920 mL x 1 g/mL = 920 g
moles water = 920 g/ 18.02 g/mol=51.1
mole fraction water = 51.1 / 51.1 + 0.605 =0.988
vapor pressure solution = 0.988 x 23.76 = 23.47 mm Hg</span>
Answer:
8 mol of hydrogen will react with 1 mol of sulfur.
Explanation:
We'll begin by writing the balanced equation for the reaction.
This is given below:
8H2 + S8 —> 8H2S
Now, let us carefully observe the mole ratio of the reactants.
This is illustrated:
The mole ratio of the reactants ( i.e H2 and S8) is 8 : 1
From the balanced equation above,
We can thus, concluded that:
8 moles of H2 will reacted with 1 mole of S8.
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Answer:
-0.74
Explanation:
Let's consider the following redox reaction.
AgCl(s) + NO(g) → Ag(s) + Cl⁻(aq) + NO₃⁻(aq)
We can identify the oxidation and reduction half-reactions.
Reduction (cathode): 1 e⁻ + AgCl(s) → Ag(s) + Cl⁻(aq)
Oxidation (anode): 2 H₂O(l) + NO(g) → NO₃⁻(aq) + 4H⁺(aq) + 3 e⁻
The standard cell potential (E°) is equal to the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red,cat - Ered,an = 0.22 V - 0.96 V = -0.74 V
