Answer:
answer is 1.A measurment of the...
Answer:
0.4515 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 10.0 mL
M₂ = 0.100 M
V₂ = 45.15 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 10.0mL = 0.100 M * 45.15 mL
M₁ = 0.4515 M
Hence, the concentration of the acetic acid = 0.4515 M
A single replacement reaction can be represented by the equation AB + C = AC + B
1 proton = 1 positive charge
1 electron = 1 negative charge
+21-19= <u>+3</u>
Paper chromatography is a tool frequently used in analytical chemistry to separate a homogeneous mixture into its components.
In paper chromatography the stationary phase is water which drenches the paper and the mobile phase is a mixture polar organic solvent and water. The various components of the homogeneous mixture is separated based on their relative solubility in either the mobile or stationary phase.