Answer: 3.6 m/s
Step-by-Step Answer:
<em>Translated from Spanish to English for other English speaking students to benefit.</em>
Question:
Determine the average speed of a mobile that has an initial speed of 3m/s and its final speed is 4.2m/s
To average anything, just put them into a fraction and divide their total by the number of things you want to average.
![\frac { ( 3 + 4.2 ) \left[ \frac { m } { s } \right] } { 2 } = \frac { 7.2 \left[ \frac { m } { s } \right] } { 2 } = 3.6 \left[ \frac { m } { s } \right]](https://tex.z-dn.net/?f=%5Cfrac%20%7B%20%28%203%20%2B%204.2%20%29%20%5Cleft%5B%20%5Cfrac%20%7B%20m%20%7D%20%7B%20s%20%7D%20%5Cright%5D%20%7D%20%7B%202%20%7D%20%3D%20%5Cfrac%20%7B%207.2%20%5Cleft%5B%20%5Cfrac%20%7B%20m%20%7D%20%7B%20s%20%7D%20%5Cright%5D%20%7D%20%7B%202%20%7D%20%3D%203.6%20%5Cleft%5B%20%5Cfrac%20%7B%20m%20%7D%20%7B%20s%20%7D%20%5Cright%5D)
En español
Para promediar cualquier cosa, solo póngalos en una fracción y divida su total por la cantidad de cosas que desea promediar.
Porque hay 2 velocidades, y queremos promediarlas, dividimos su total por 2.
![\frac { ( 3 + 4.2 ) \left[ \frac { m } { s } \right] } { 2 } = \frac { 7.2 \left[ \frac { m } { s } \right] } { 2 } = 3.6 \left[ \frac { m } { s } \right]](https://tex.z-dn.net/?f=%20%5Cfrac%20%7B%20%28%203%20%2B%204.2%20%29%20%5Cleft%5B%20%5Cfrac%20%7B%20m%20%7D%20%7B%20s%20%7D%20%5Cright%5D%20%7D%20%7B%202%20%7D%20%3D%20%5Cfrac%20%7B%207.2%20%5Cleft%5B%20%5Cfrac%20%7B%20m%20%7D%20%7B%20s%20%7D%20%5Cright%5D%20%7D%20%7B%202%20%7D%20%3D%203.6%20%5Cleft%5B%20%5Cfrac%20%7B%20m%20%7D%20%7B%20s%20%7D%20%5Cright%5D)
Answer:
formed by the process of glaciation.
Explanation:
Answer:
a flow of negatively charged electrons is an
electric current
Answer:
Covalent
Explanation:
water molecule consists of two atoms of hydrogen connected by covalent bonds to the same atom of oxygen. Atoms of oxygen are electronegative and attract the shared electrons in their covalent bonds.
Answer:
- <u> From your frame of reference, the speed of your friend is zero.</u>
Explanation:
The<em> speed</em> from a <em>frame of reference</em> is the magnitude of the change of the position per unit of time in that frame of reference.
When it is said that, to a <em>stationary observer</em> you have a <em>speed of 9m/s</em>, it means that the observer "measures" tha your position, in a moment, changes 9 m per second.
Since both you and your friend are sit still on the same spinning merry-go-round, neither of you will change positions with respect to the other, meaning that you will perceive that your friend will not move, from your frame of reference. That is, if you are isolated from the rest of the universe, and the merry-go-round continues spining uniformly, you cannot detect any movement of your friend, which means that from your frame of reference, the speed of your friend is zero.
