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Rasek [7]
3 years ago
8

I need help with this question for homework.

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
4 0
\sf\frac{72}{126}=\frac{36}{x}\\Cross~multiply\\72x=126(36)\\Solve~for~x\\x=63

\sf\frac{72}{126}=\frac{24}{y}\\Cross~multiply\\72y=126(24)\\Solve~for~y\\y=42

\sf\frac{72}{126}=\frac{12}{z}\\Cross~multiply\\72z=126(12)\\Solve~for~z\\z=21

And three more equivalent ratios are filled in the table:

<span>___________________ _____________
I_72__I_36_I_24_I_12_I I_4_I_8__I_16_I
I_126_I_63_I_42_I_21_I I_7_I_14_I_28_I

I hope that helps :)</span>



Leviafan [203]3 years ago
3 0
Here's the method on the first one (36)

The ratio is \frac{72}{126}=\frac{36}{63}=\frac{12}{21}=\frac{4}{7}, hence if we call xthe number below 36, we will have \frac{36}x=\frac{72}{126}=\frac{4}7 hence x=\frac{36\cdot7}4=63

I_72__I_36_I_24_I_12_I
<span>I_126_I_63_I_42_I_21_I

</span>
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Answer:

The mean and standard deviation of the corrected pH measurements are 6.63 and 3.8025 respectively.

Step-by-step explanation:

We can correct the values of the mean and standard deviation using the properties of the mean and the variance.

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The mean and standard deviation of the original value X are 4.9 and 1.5 respectively.

Then, we can apply the properties of the mean as:

E(Y)=E(1.3(X+0.2))=1.3E(X+0.2)=1.3E(X)+1.3*0.2\\\\E(Y)=1.3E(X)+0.26\\\\E(Y)=1.3*4.9+0.26=6.37+0.26=6.63

For the standard deviation, we apply the properties of variance:

V(Y)=V(1.3(X+0.2))\\\\V(Y)=1.3^2\cdot V(X+0.2)\\\\V(Y)=1.69\cdot V(X)\\\\V(Y)=1.69\cdot 1.5^2=1.69\cdot 2.25=3.8025

The properties that have been applied are:

1.\,E(aX)=aE(X)\\\\ 2.\,E(X+b)=E(X)+b\\\\3.\,V(aX)=a^2V(X)\\\\4.\,V(X+b)=V(X)+0

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Actually the correct answer would be letter D. 89.7 mark as brainliest thanks
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