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Naily [24]
3 years ago
12

PLS HURRY THIS IS DUE IN 5 mins

Physics
1 answer:
Dmitrij [34]3 years ago
7 0

Answer:

(a) Waves P and Q have the same  wavelength but wave P has twice the  amplitude of wave Q.

(b) Waves Q and R have the same amplitude  but wave R has twice the wavelength  of wave Q.

(c) Wave  T shows a steady frequency but changing amplitude.

(d) Wave  S shows steady amplitude but a changing frequency.

e) Waves  Q and R have a low amplitude and a steady  frequency.

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[O.04H]The table below shows the use of some energy production methods over time.
mr Goodwill [35]

I think The coastal areas were highly polluted

8 0
3 years ago
Read 2 more answers
NEES HELP!!!!
OLga [1]

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

6 0
2 years ago
Light of wavelength 580 nm is incident on a slit of width 0.30 mm. An observing screen is placed 2.0 m past the slit. Find the d
uysha [10]

Answer:

Y = 3.87 x 10⁻³ m = 3.87 mm

Explanation:

This problem can be solved by using Young's double-slit experiment formula:

Y = \frac{\lambda L}{d}

where,

Y = fringe spacing = ?

L = slit to screen distance = 2 m

λ = wavelength of light = 580 nm = 5.8 x 10⁻⁷ m

d = slit width = 0.3 mm = 3 x 10⁻⁴ m

Therefore,

Y = \frac{(5.8\ x\ 10^{-7}\ m)(2\ m)}{3\ x\ 10^{-4}\ m}

<u>Y = 3.87 x 10⁻³ m = 3.87 mm</u>

3 0
3 years ago
What is the minimum value of the friction coefficient between the boxes that will keep them from slipping when the 100 N force i
CaHeK987 [17]

Answer:

The friction coefficient's minimum value will be "0.173".

Explanation:

The given query seems to be incomplete. Below is the attached file of the complete question.

According to the question,

(a)

The net friction force's magnitude will be:

⇒ F_{net}=ma

           =5\times 1.7

           =8.5 \ N

(b)

For m₃,

⇒ ma=\mu m_3 g

Or,

⇒    \mu=\frac{a}{g}

          =\frac{1.7}{9.8}

          =0.173

5 0
3 years ago
A particular star cluster contains stars all with the same apparent magnitude of +4. Near the cluster (and at the same distance
777dan777 [17]

Answer:

3,000 stars.

Explanation:

Subtract the magnitude of the single star from the magnitude of the star cluster.

(+4) - (+1) = +3

Then multiply your answer by 1000

= 3,000 is a stars.

5 0
3 years ago
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