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Georgia [21]
3 years ago
14

Care este pozitia unui mobil cand t(s)=14 si x(m)=12?​

Physics
1 answer:
mario62 [17]3 years ago
3 0

name shrawan sha

DtD_LpOZ3Xm_0ff

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James took two pea plants, placing one in a dark closet and the other on a sunny window sill. Both are located in air-conditione
Fudgin [204]

The constant is the temperature of the air that the plants get.

The independent variable is the thing that YOU control.  That's the amount of sunlight each plant gets.

The <em>dependent variable</em> is anything that's caused by changes in the independent variable.  That's the growth of the plants.

5 0
3 years ago
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When can a high speed velocity cause damage?'
sweet-ann [11.9K]

Answer:

50 Mph.

Explanation:

According to the National Severe Storms Laboratory, winds can really begin to cause damage when they reach <em><u>50 mph</u></em>. But here’s what happens before and after they reach that threshold, according to the Beaufort Wind Scale (showing estimated wind speeds): - at 19 to 24 mph, smaller trees begin to sway.

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3 years ago
What is the relationship between the wavelength of the peak (maximum) of the Gaussian curve and the temperature in degrees Kelvi
Tomtit [17]

Answer:

\lambda_{max}=\frac{b}{T}

Explanation:

Wien's displacement law states that the radiation of the black body curve for different temperatures will give peak values at different wavelengths and this wavelength is related inversely to the temperature.

Formally the law of Wien displacement states that the black body's spectral radiation per unit of wavelength, will give peaks at the wavelength of  \lambda_{max} which is given by the mathematical expression.

\lambda_{max}=\frac{b}{T}

Here, b is proportionality constant  with value of 2.897771955...\times 10^{-3} mK

The wavelength of the peak of the Gaussian curve is inversely related to temperature in degree kelvin.

3 0
3 years ago
Hi im a little stuck on this question that came from my textbook in class it got a little confusing for me because i really dont
koban [17]

Consult the attached free body diagram.

By Newton's second law, the net force on the crate acting parallel to the surface is

∑ F[para] = (370 N) cos(-20°) - f = 0

(this is the x-component of the resultant force)

where

• (370 N) cos(-20°) = magnitude of the horizontal component of the pushing force

• f = magnitude of kinetic friction

The crate is moving at a constant speed and thus not accelerating, so the crate is in equilibrium.

Solve for f :

f = (370 N) cos(-20°) ≈ 347.686 N

The net force acting perpendicular to the surface is

∑ F[perp] = n - 1480 N - (370 N) sin(-20°) = 0

(this is the y-component of the resultant force)

where

• n = magnitude of normal force

• 1480 N = weight of the crate

• (370 N) sin(-20°) = magnitude of the vertical component of push

The crate doesn't move up or down, so it's also in equilibrium in this direction.

Solve for n :

n = 1480 N + (370 N) sin(-20°) ≈ 1606.55 N ≈ 1610 N

Then the coefficient of kinetic friction is µ such that

f = µn   ⇒   µ = f/n ≈ 0.216

7 0
2 years ago
A boat sails along the shore. To an observer, the boat appears to move at a speed of 11 m/s, and a man on the boat walking forwa
amid [387]

You first subtract the speed at which the man is moving (11 m/s) from the rate the boat is moving (12.4 m/s). Which equals 1.4, then divide it by 6 meters, as the man is moving relative to the boat.

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