The change in momentum for an object is equal to

Physics

1 answer:

koban [17]3 years ago

4 0

Answer:

We conclude that the change in momentum of a body is equal to the impulse experienced by a body.

Explanation:

Considering the equation

F • t = m • Δ v

Here,

m • Δ v is basically a change in momentum of a body which is equal to the mass of the object multiplied by the change in its velocity.

Also,

F • t is called the impulse of the object.

In the formula, it is clear that the impulse experienced by a body during the collision is basically a change in the momentum of the body.

In other words, the change in momentum of a body is equal to the impulse experienced by a body.

Therefore, we conclude that the change in momentum of a body is equal to the impulse experienced by a body.

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The voltage of electricity traveling away from a power plant is very high. How high may it be? Why is the voltage so high?

sashaice [31]

- The voltage travelling away from a power plant through transmission lines is very high, and it is typically of hundreds of kilovolts (typical values are between 138 kV and 765 kV).

- The main reason to use these high values of voltage is to reduce power dissipation.
In fact, the cables that are used to transmit electricity have a certain resistance R which is fixed. The power generated from the power plant and that should be transmitted through the lines is P, and it is also fixed.
The power dissipated through the cables is calculated as
$P_{diss}=I^2 R = (\frac{P}{V} )^2 R$
where I is the current and V the voltage.
As it can be seen, using higher voltages reduce the amount of power dissipated through the lines (while using higher currents will have the opposite effect).

8 0

3 years ago

The x and y components of vector S are -30.0 m and +40.0 m, respectively. Find the magnitude of S and the angle between the dire

34kurt

Answer:

The given vector can be represented in unit vector as

$\overrightarrow{w}=-30\widehat{i}+40\widehat{j}$

The magnitude of any vector $\overrightarrow{r}=u\widehat{i}+v\widehat{j}$ is given by

$|w|=\sqrt{u^{2}+v^{2}}$

Applying values we get

$|w|=\sqrt{-30^{2}+40^{2}}\\\\|r|=50$

We know that positive x axis in vertorial form is represented as

$\overrightarrow{r}=\widehat{i}$

taking dot product of both the vector's we get

$\overrightarrow{r}.\overrightarrow{w}=|r||w|cos(\theta )\\\\\therefore cos(\theta )=\frac{(-30\widehat{i}+40\widehat{j}).\widehat{i}}{50}\\\\\therefore \theta =cos^{-1}(\frac{-30}{50})=126.86^{o}$