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Nimfa-mama [501]
3 years ago
6

You drop two balls from a tower, one of mass m and the other of mass 3m.

Physics
2 answers:
denpristay [2]3 years ago
5 0

a. Second ball of mass 3m has the larger kinetic energy than the first ball of mass m

\texttt{ }

<h3>Further explanation</h3>

Let's recall the Kinetic Energy formula:

\boxed {E_k = \frac{1}{2}mv^2 }

<em>Ek = kinetic energy ( J )</em>

<em>m = mass of object ( kg )</em>

<em>v = speed of object ( m/s )</em>

\texttt{ }

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

mass of first ball = m

mass of second ball = 3m

<u>Asked:</u>

ratio of kinetic energy of the balls = Ek₁ : Ek₂ = ?

<u>Solution:</u>

Ek_1 : Ek_2 = \frac{1}{2}m_1 v_1^2 : \frac{1}{2}m_2 v_2^2

Ek_1 : Ek_2 = \frac{1}{2}m_1 (2gh) : \frac{1}{2}m_2 (2gh)

Ek_1 : Ek_2 = m_1gh : m_2gh

Ek_1 : Ek_2 = m_1 : m_2

Ek_1 : Ek_2 = m : 3m

Ek_1 : Ek_2 = 1 : 3

Ek_2 = 3Ek_1

\texttt{ }

<h3>Conclusion:</h3>

Second ball of mass 3m has the larger kinetic energy than the first ball of mass m

\texttt{ }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Energy

neonofarm [45]3 years ago
3 0
The potential energy that the ball has at the top of the tower is its kinetic energy when it hits the ground. The second ball has more potential energy at the top, because you did more work on it to carry it up there. So it has more KE at the bottom. (A)
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Explanation:

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5 0
2 years ago
a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro
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Answer:

\theta=53.13^o

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

V_x=V_{ox}=V_ocos\theta

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The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

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Dividing by sin\theta

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Rearranging

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