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Nimfa-mama [501]
3 years ago
6

You drop two balls from a tower, one of mass m and the other of mass 3m.

Physics
2 answers:
denpristay [2]3 years ago
5 0

a. Second ball of mass 3m has the larger kinetic energy than the first ball of mass m

\texttt{ }

<h3>Further explanation</h3>

Let's recall the Kinetic Energy formula:

\boxed {E_k = \frac{1}{2}mv^2 }

<em>Ek = kinetic energy ( J )</em>

<em>m = mass of object ( kg )</em>

<em>v = speed of object ( m/s )</em>

\texttt{ }

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration (m / s²)v = final velocity (m / s)</em>

<em>u = initial velocity (m / s)</em>

<em>t = time taken (s)</em>

<em>d = distance (m)</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

mass of first ball = m

mass of second ball = 3m

<u>Asked:</u>

ratio of kinetic energy of the balls = Ek₁ : Ek₂ = ?

<u>Solution:</u>

Ek_1 : Ek_2 = \frac{1}{2}m_1 v_1^2 : \frac{1}{2}m_2 v_2^2

Ek_1 : Ek_2 = \frac{1}{2}m_1 (2gh) : \frac{1}{2}m_2 (2gh)

Ek_1 : Ek_2 = m_1gh : m_2gh

Ek_1 : Ek_2 = m_1 : m_2

Ek_1 : Ek_2 = m : 3m

Ek_1 : Ek_2 = 1 : 3

Ek_2 = 3Ek_1

\texttt{ }

<h3>Conclusion:</h3>

Second ball of mass 3m has the larger kinetic energy than the first ball of mass m

\texttt{ }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Energy

neonofarm [45]3 years ago
3 0
The potential energy that the ball has at the top of the tower is its kinetic energy when it hits the ground. The second ball has more potential energy at the top, because you did more work on it to carry it up there. So it has more KE at the bottom. (A)
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Answer: The students will determine the two fixed points of the thermometer:

Lower fixed point = 0 degree Celsius

Upper fixed point = 100 degree Celsius

Then divide the thermometer with equal intervals

The room temperature will be the point at which the themometric substance remains constant when rising from ice point.

Explanation:

Apparatus available:

Unmarked thermometer

250 cm3 glass beaker

crushed ice 

water

heatproof mat 

clamp, boss and stand

meter rule

Added apparatus

Bunsen burner

Stirrer

Method

The students will determine the two fixed points of the thermometer:

Lower fixed point = 0 degree Celsius

Upper fixed point = 100 degree Celsius

Then divide the thermometer with equal intervals

Procedures

Set up the apparatus of illustrated in the attached figure.

Immerse the unmarked thermometer into the ice in the beaker.

When the level indicated by the thermometric substance remains steady after some time, a mark will be made at that point. This mark will corresponds to the ice point (lower fixed point) and is assigned the value of 0 °C.

You may add little water and continue to stir gently.

The themometric substance will start to rise and stop when it reaches room temperature. Mark the point but do not assign any value

Place the beaker on bunsen burner and boil the water. The themometric substance will continue to rise and remain constant at upper fixed point

This mark will corresponds to the steam point (upper fixed point) and is assigned the value of 100 °C.

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