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Alenkasestr [34]

3 years ago

15

What is the function of layer of air trapped under the hovercraft

1 answer:

aev [14]3 years ago

3 0

Answer:b

Explanation:

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How long does it take for the speed of light and sound to travel around the world

irina [24]

-- Light travels straight, not around in a circle. But if it did, it would cover
a distance equal to the length of the equator in about <em>0.13 second</em>.

-- At the speed of sound (in air at standard temperature and pressure),
it would take about <em>32.6 hours </em>to cover the same distance.

6 0

3 years ago

A ball weighing 1 lb is attached to a string 2 feet long and is whirled in a vertical circle at a constant speed of 10 ft/sec.

fredd [130]

Explanation:

It is given that,

Mass of the ball, m = 1 lb

Length of the string, l = r = 2 ft

Speed of motion, v = 10 ft/s

(a) The net tension in the string when the ball is at the top of the circle is given by :

$F=\dfrac{mv^2}{r}-mg$

$F=m(\dfrac{v^2}{r}-g)$

$F=1\ lb\times (\dfrac{(10\ ft/s)^2}{2}-1\ lb\times 32\ ft/s^2)$

F = 18 N

(b) The net tension in the string when the ball is at the bottom of the circle is given by :

$F=\dfrac{mv^2}{r}+mg$

$F=m(\dfrac{v^2}{r}+g)$

$F=1\ lb\times (\dfrac{(10\ ft/s)^2}{2}+1\ lb\times 32\ ft/s^2)$

F = 82 N

(c) Let h is the height where the ball at certain time from the top. So,

$T=mg(\dfrac{r-h}{r})+\dfrac{mv^2}{r}$

$T=\dfrac{m}{r}(g(r-h)+v^2)$

Since, $v^2=u^2-2gh$

$T=\dfrac{m}{r}(u^2-3gh+gr)$

Hence, this is the required solution.

6 0

3 years ago

A cube 10.0 cm on each side has a density of 2.053 x 10^4 kg/m^3. It’s apparent weight in fresh water is 192 N. Find the buoyant

insens350 [35]

Answer:

9 N

Explanation: Given that L = side of the cube = 10cm = 0.1m

Mass = Density * Volume

Let’s determine the volume of the cube in m^3.

V = L^3

V = 0.1^3 = 0.001m^3

Mass = 0.001 * 2.053 * 10^4 = 20.53kg

Weight = 20.53 * 9.8 = 201.194

Buoyant force = 201.194 – 192 = 9.194 N

This is approximately 9 N.

6 0

4 years ago

Two streams merge to form a river. One stream has a width of 8.9 m, depth of 3.8 m, and current speed of 2.3 m/s. The other stre

SpyIntel [72]

<h2>Depth of river is 4.48 m</h2>

Explanation:

Discharge = Area x Velocity

Discharge of river = Discharge of stream 1 + Discharge of stream 2

$A_rv_r=A_1v_1+A_2v_2$

Area of stream 1 = w₁ x d₁ = 8.9 x 3.8 = 33.82 m²

Area of stream 2 = w₂ x d₂ = 6.5 x 3.9 = 25.35 m²

Velocity of stream 1 = 2.3 m/s

Velocity of stream 2 = 2.6 m/s

Velocity of river = 3 m/s

$\texttt{Area of river = }w_r\times d_r=10.7\times d_r$

Substituting

$A_rv_r=A_1v_1+A_2v_2\\\\10.7\times d_r\times 3=33.82\times 2.3+25.35\times 2.6\\\\d_r=4.48m$

Depth of river = 4.48 m

7 0

3 years ago

Longitudinal seismic waves are known as

Helga [31]

Its “A“ primary waves!!!!!!

3 0

3 years ago

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