Answer:
the value of the equilibrium constant Kp for this reaction is 0.275
Explanation:
Step 1: Data given
Pressure HCl at the equilibrium = 18.0 atm
Pressure H2 at the equilibrium = 25.4 atm
Pressure Cl2 at the equilibrium = 46.4 atm
Step 2: The balanced equation
H2(g) + Cl2(g) → 2 HCl(g)
Step 3: Calculate the value of the equilibrium constant Kp for this reaction
Kp = (pHCl)² / (pH2*pCl2)
Kp = 18.0² / (25.4 * 46.4)
Kp = 324 / 1178.56
Kp = 0.275
the value of the equilibrium constant Kp for this reaction is 0.275
6 miles of H2O is equal to 12 Hydrogen molecules and 6 oxygen molecules. Equaling 18 in total.
Answer:
The molecular formula of glucose is C₆H₁₂O₆
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of smallest whole number of atoms.
Molecular formula:
It gives the total number of atoms in a molecule of compound.
The molecular formula and empirical formula can be related as follow:
Molecular formula = n × empirical formula
Given data:
Empirical formula = CH₂O
Molecular formula = ?
It is stated in given problem that molecular formula is the 6 times of the empirical formula.
Molecular formula = n × empirical formula
Molecular formula = 6 × CH₂O
Molecular formula = C₆H₁₂O₆
The molecular formula of glucose is C₆H₁₂O₆.
<span>Energy is absorbed and then released to form an emission line.
When electrons absorb energy they increase there energy level. This is only temporary and the excited electron then relaxes back down to its original energy level releasing energy.
The energy is released in form of EM radiation of a specific frequency depending on the element and how many energy levels the electron relaxes.
This forms an emission line.</span><span />
