‘By using displacement reactions it is possible to deduce the order of reactivity of the halogens.’

Chemistry

1 answer:

Rashid [163]4 years ago

7 0

Answer:

Explanation:

The halogens have seven electrons in their outermost shell. Each halogen atom lacks a single electron to make their octet a complete one. Elements in the halogen group are univalent and also acceptors of electrons. They are all non-metals and oxidizing agents. The oxidizing power of the halogens decreases from top to down the group. This is why the more powerful halogens displaces a less powerful one from simple salts.

Cl₂ + 2KBr → 2KCl + Br₂

Cl₂ + 2KI → 2KCl + I₂

Br₂ + 2KI → 2KBr + I₂

I₂ + 2KCl → No reaction

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In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.

olga nikolaevna [1]

Answer:

a. The second run will be faster.

d. The second run has twice the surface area.

Explanation:

The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.

$A=\pi ^{1/3} (6V)^{2/3}$

The area of the 10.0 cm³-sphere is:

$A=\pi ^{1/3} (6.10.0)^{2/3}=22.4cm^{2}$

The area of each 1.25 cm³-sphere is:

$A=\pi ^{1/3} (6. 1.25)^{2/3}=5.61cm^{2}$

The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²

The ratio of 8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00

Since the surface area is doubled, the second run will be faster.

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3 years ago

Compare uniformitarianism with catastrophism

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Ammonium hydrogen sulfide (NH4HS) can

Sergeu [11.5K]

$K_c = \frac{[NH_2]^{1}[H_2S]^{1}}{[NH_2HS]^{1}}$ is the equilibrium constant expression for

NH₂HS(S) → NH₂(g) + H₂S(g). Hence, option A is correct.

<h3>Definition of equilibrium constant.</h3>

A number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.

Equilibrium constant for the NH₂HS(S) → NH₂(g) + H₂S(g) will be:

$K_c = \frac{[Product]^{coefficient}}{[Reactantt]^{coefficient}}$