All categories

3 years ago

A cell is classified as eukaryotic if the cell

Physics

2 answers:

oee [108]3 years ago

7 0

b- contains a nucleus

bezimeni [28]3 years ago

5 0

Eukaryotic cells contain membrane-bound organelles, including a nucleus.Prokaryotic cells<span> do not contain a nucleus or any other membrane-bound organelle. i think thats the answer but if im wrong im sorry</span>

You might be interested in

An energy resource that can be replaced in a reasonable short period of time is call an

Semenov [28]

A Renewable resource

6 0

3 years ago

Read 2 more answers

that delivers oxygen to your body and In the video your blood is compared to a picks up CO2 to be released out when you breath.

sweet-ann [11.9K]

I’m a bit confused. What’s the question?

4 0

3 years ago

8. Mark is sitting in a chair, legs out in front of him resting on an ottoman. His knees are.....

anyanavicka [17]

His knees are flat in front of him or 180 degrees, i hope that answered your question

5 0

3 years ago

Read 2 more answers

1.10) For a fixed mass of gas at constant temperature, if the volume of the gas (V) increases to twice its original amount, the

Aliun [14]

B. 1/2p
From the relation
P1V1=P2V2
P2=P1V1/V2
If everything equals one
P2=1*1/2(1)
That would equal 1/2
I hope this helps
Please mark as brainliest

7 0

3 years ago

Read 2 more answers

The current theory of the structure of the

IRISSAK [1]

1) The mass of the continent is $3.3\cdot 10^{21} kg$

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

We start by finding the volume of the continent. We have:

$L = 5850 km = 5.85\cdot 10^6 m$ is the side

$t = 35 km = 3.5\cdot 10^4 m$ is the depth

So the volume is

$V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3$

We also know that its density is

$d=2750 kg/m^3$

Therefore, we can find the mass by multiplying volume by density:

$m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg$

The kinetic energy of the continent is given by:

$K=\frac{1}{2}mv^2$

where

$m=3.3\cdot 10^{21} kg$ is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

$1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s$

So, the speed is:

$v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s$

So, we can now find the kinetic energy:

$K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J$

Here we have a jogger of mass

m = 78 kg

And the jogger has the same kinetic energy of the continent, so

K = 624 J

The kinetic energy of the jogger is given by

$K=\frac{1}{2}mv^2$

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(624)}{78}}=4 m/s$

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

3 0

3 years ago