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3 years ago

8

The acceleration of a falling rock that was initially moving 5 m/s, and had a final velocity of 11 m/s after accelerating for 3

seconds.

1 answer:

yanalaym [24]3 years ago

3 0

Answer:

2 m/s²

Explanation:

Given:

v₀ = 5 m/s

v = 11 m/s

t = 3 s

Find: a

v = at + v₀

11 m/s = a (3 s) + 5 m/s

a = 2 m/s²

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2 years ago

Why is wavelength the main limiting factor on limit of resolution in light microscopy?

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3 years ago

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3 years ago

A wire with radius 23 cm has a current of 7 A which is distributed uniformly through its cross sectional area. If you were to us

Rina8888 [55]

Answer:

The magnetic induction of the magnetic field is 0.0005293 mT

Explanation:

Data given

I = 7 A = the total current in the wire

r = 23 cm = the radius of the wire = 0.23 meter

r' = 2cm = the measurement point, which should be inside the wire = 0.02 meter

Let's consider the current density is constant in the wire, ⇒ the current enclosed is a function of the enclosed area

I(enclosed) = Jπ r ²

we can consider the current density as the total current over the whole area:

I(enclosed) = I / (πr ²) * πr' ²

I(enclosed) = (I* r'²)/ (r ²)

with I = total current in the wire = 7A

With r = the radius of wire = 0.23 meter

with r' = the distance of point from the center of wire 0.02 meter

We plug this into ampere's law:

∮ *B *dl =μ 0 * (I* r'²)/ (r ²)

with B = Magnetic flux density (in Tesla) or magnetic induction

with dl = an infinitesimal element (a differential) of the curve C

with µ0 = the magnectic constant = 4π*10^−7 H/m

We can simplify this, by using an Amperian loop can write this as:

B *( 2 π r') = μ 0 * (I* r'²)/ (r ²)

Because the circumference of a circle is 2 π r , when we integrate over length at a distance r ′ from the center of wire whose crossection is a circle we get 2 π r ′

When we isolate B, we get:

B = µo *(Ir'/2 π r ²)

B = 4π*10^−7 * ((7*0.02)/2*π*0.23²)

B =5.293 *10 ^-7 T = 0.0005293 mT

The magnetic induction of the magnetic field is 0.0005293 mT

6 0

3 years ago

A flat metal washer is heated. As the washer's temperature increases, what happens to the hole in the center? A flat metal washe

STALIN [3.7K]

To solve this exercise it is necessary to take into account the concepts related to thermal expansion.

The thermal expansion is given by the function,

$\Delta L = L_0 \alpha \Delta T$

Where,

$\Delta L=$ Change in Length

$\Delta T =$ Change in Temperature

$\alpha =$ Coeficiente de dilatación lineal

$L_0 =$ Initial Length

By quickly deducing the formula, we can realize that the greater the change in temperature, the greater the change in the length of the radius.

The change in length is proportional to the change in temperature. Considering that the other two terms are constant we have that the correct one would be: <em>The hole in the center of the washer will expand.</em>

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3 years ago