With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x N and 66 degrees
ELECTRIC FORCE (F)
F =
Where K = 9 x N/
The distance between and can be calculated by using Pythagoras theorem.
d =
d = 46.7 cm = 0.467 m
For force , substitute all the parameters into the formula above
= (9 x x 3 x 1)/
= 2.7 x /0.218
= 1.24 x N
For force , substitute all the parameters into the formula above
= (9 x x 3 x 4)/
= 1.08 x /0.1089
= 9.92 x N
For force , substitute all the parameters into the formula above
= (9 x x 3 x 2)/
= 5.4 x /0.1089
= 4.96 x N
Summation of forces on Y component will be
= - Sin 45
= 9.92 x - 1.24 x Sin 45
= 9.04 x N
Summation of forces on X component will be
= - Cos 45
= 4.96 x - 1.24 x Sin 45
= 4.08 x N
Net Force =
Net force =
Net force = 9.9 x N
The direction will be
Tan ∅ = /
Tan ∅ = 9.04 x / 4.08 x
Tan ∅ = 2.216
∅ = (2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816
Question 9 is 100 N.
Question 10 is No, the bike's motion is not changing so it could be at rest or moving at a constant velocity.
Question 11 is Be doubled.
Question 12 is Ella is correct.
Hope i helped.
Answer:
<em>The amount of electric charge transported = 0.192 C</em>
Explanation:
Electric Charge: This is defined as the product of electric current and time in an electric circuit, The S.I unit of electric charge is Coulombs (C)
Q = It..................... Equation 1
Where Q = Electric charge, I = electric current, t = time.
<em>Given:</em> I = 285 mA, t = 674 milliseconds.
<em>Conversion: (i) Convert from 285 mA to A = (285/1000) A = 0.285 A</em>
<em> (ii) convert from 674 milliseconds to seconds = (674/1000) s = 0.674 s </em>
Substituting these values into equation 1
Q = 0.285 × 0.674
<em>Q = 0.192 C</em>
<em>Therefore the amount of electric charge transported = 0.192 C</em>
<em></em>
<em></em>
That is very true, but what is the question asking you.
Answer
given,
mass of glider = 0.23 Kg
spring constant = k = 4.50 N/m
spring stretched to 0.130 m
The springs potential energy =
U = 0.038 J
at x = 0,the only energy will be kinetic .
v² = 0.3304
v = 0.575 m/s
displacement of the glider
using conservation of energy
x = 0.678 m