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Lisa [10]
3 years ago
6

Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2.

Gun #1 weighs three times as much as gun #2. The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is:

Physics
1 answer:
GalinKa [24]3 years ago
8 0

Answer:

The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is equal to 2 : 1

Explanation:

Detailed explanation and calculation is shown in the image below

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What is the energy in the spark produced by discharging the second capacitor? 1. The same as the discharge spark of the first ca
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Complete Question

The two isolated parallel plate capacitors be-  low, one with plate separation d and the other  with D > d, have the same plate area A and

are given the same charge Q.

What is the energy in the spark produced by discharging the second capacitor?

 1. The same as the discharge spark of the first capacitor

2. More energetic than the discharge spark of the first capacitor

3. Less energetic than the discharge spark of the first capacitor

Answer:

The correct option is 2

Explanation:

The formula for the energy stored in the capacitor is

             U = \frac{Q^2}{2C}

And generally the formula for finding the capacitance of a capacitor is

               C = \frac{\epsilon_oA}{d}

We can denote the capacitance of the first capacitor as C_1 = \frac{\epsilon_oA}{d}

          and   denote the capacitance of the second  capacitor as C_2 = \frac{\epsilon_oA}{D}

Looking at this formula we can see that C varies inversely with d            

as D > d it means that C_1 > C_2

                Since the charge is constant

                         U\  \alpha\ \frac{1}{C} i.e U varies inversely with C

           So C_1 > C_2   => U_2 >U_1

This means that the energy of spark would be more for capacitor two compared to capacitor one

The correct option is 2

6 0
3 years ago
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