Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2.
Gun #1 weighs three times as much as gun #2. The ratio of the momentum imparted to gun #1 to that imparted to gun #2 is:
1 answer:
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Explanation:
It is given that,
Diameter of loop, d = 1.4 cm
Radius of loop, r = 0.7 cm = 0.007 m
Magnetic field,
(A) Magnetic field of a current loop is given by :
I is the current in the loop
I = 27.85 A
(B) Magnetic field at a distance r from a wire is given by :
r = 0.00222 m
Hence, this is the required solution.