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3 years ago

Determine the number of moles of oxygen atoms in each of the following.

Chemistry

1 answer:

zhuklara [117]3 years ago

6 0

Answer :

Part 1: 4.93 moles of $H_2O_2$ contains 9.86 moles of oxygen atoms.

Part 2: 2.01 moles of $N_2O$ contains 2.01 moles of oxygen atoms.

Explanation :

Part 1: 4.93 mol $H_2O_2$

In 1 mole of $H_2O_2$ , there are 2 atoms of hydrogen and 2 atoms of oxygen.

As, 1 mole of $H_2O_2$ contains 2 moles of oxygen atoms.

So, 4.93 moles of $H_2O_2$ contains $4.93\times 2=9.86$ moles of oxygen atoms.

Thus, 4.93 moles of $H_2O_2$ contains 9.86 moles of oxygen atoms.

Part 2: 2.01 mol $N_2O$

In 1 mole of $N_2O$ , there are 2 atoms of nitrogen and 1 atom of oxygen.

As, 1 mole of $N_2O$ contains 1 mole of oxygen atoms.

So, 2.01 moles of $N_2O$ contains $2.01\times 1=2.01$ moles of oxygen atoms.

Thus, 2.01 moles of $N_2O$ contains 2.01 moles of oxygen atoms.

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[A] = 0.009 00 mol·L⁻¹

Calculation :

$\begin{array}{rcl}\dfrac{1}{\text{[A]}} & = & \dfrac{1}{\text{[A]}_{0}}+ kt\\\\\dfrac{1}{0.00900 }& = & \dfrac{1}{0.0100} + 2.4 \times 10^{-21} \, t\\\\111.1&=& 100.0 + 2.4 \times 10^{-21} \, t\\\\11.1& = & 2.4 \times 10^{-21} \, t\\t & = & \dfrac{11.1}{ 2.4 \times 10^{-21}}\\\\& = & \mathbf{4.6 \times 10^{21}}\textbf{ s}\\\end{array}\\\text{It will take $\large \boxed{\mathbf{4.6 \times 10^{21}}\textbf{ s}}$ for the HI to decompose}$

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Alenkasestr [34]

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2 years ago

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The solution would be like this for this specific problem:

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Simplest formula = C5H10

I hope this helps and if you have any further questions, please don’t hesitate to ask again.

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