Answer: a) vcar= 7 m/s ; b) a train= 0.65 m/s^2
Explanation: By using the kinematic equation for the car and the train we can determine the above values of the car velocity and the acceletarion of the train, respectively.
We have for the car
distance = v car* t, considering the length of train (81.1 m) travel by the car during the first 11.6 s
the v car = distance/time= 81.1 m/11.6s= 7 m/s
In order to calculate the acceleration we have to use the kinematic equation for the train from the rest
distance train = (a* t^2)/2
distance train : distance travel by the car at constant speed
so distance train= (vcar*36.35)m=421 m
the a traiin= (2* 421 m)/(36s)^2=0.65 m/s^2
Answer:
sum of all forces on the air plane must be ZERO
So both forces must be of same magnitude
Explanation:
As we know that airplane is moving with uniform speed is horizontal plane is a straight line
so the motion of the air plane is uniform without any acceleration
So we will have
acceleration must be zero
now by Newton's law
so sum of all forces on the air plane must be ZERO
Answer:
W = F * S = Newtons * Distance = Joules (definition)
Joules and KiloJoules are obviously methods of describing energy
F = M a = kg * m / s^2 definition of force
F * S = kg * m^2 / s^2 also describes work
