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fgiga [73]
3 years ago
11

Jerusha and anavi are working very hard to tend their organic veggie garden when jerusha sees a bunny nibbling on a tender letuc

e leaf. In a fit of rage, anavi chases the fluffy little rabbit across the yard. The bunny darts from rest to 16km/s in 3 seconds. What is the innocent little bunny's average acceleration?
Physics
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

Explanation:

Given:

Initial Velocity, u = 0 km/s (at rest)

Final Velocity, v = 16 km/s

Time taken, t = 3 sec

acceleration, a = (v - u)/t

= (16 - 0)/3

= 5.33 km/s^2

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How many milligrams in 1 gram. ??? HELP !!!
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3 years ago
Read 2 more answers
An object at rest does not _____ and an object in motion does not _____, unless an _____ force acts upon it
mel-nik [20]

Answer:

An object at rest does not move and an object in motion does not change its velocity, unless an external force acts upon it

Explanation:

This statement is also known as Newton's first law, or law of  inertia.

It states that the state of motion of an object can be changed only if there is an external force (different from zero) acting on it: therefore

- If an object is at rest, it will remain at rest if there is no force acting on it

- If an object is moving, it will continue moving at constant velocity if there is no force acting on it

This phenomenon can be also understood by looking at Newton's second law:

F = ma

where

F is the net force on an object

m is the mass

a is the acceleration

If the net force is zero, F = 0, the acceleration of the object is also zero, a = 0: therefore, the velocity of the object does not change, and it will continue moving at the same velocity (which can be zero, if the object was at rest).

5 0
3 years ago
Students had two batteries and two different resistors. During four trials, they build four different circuits and measure the c
Darina [25.2K]

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Explanation:

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3 years ago
If he leaves the ramp with a speed of 35.0 m/s and has a speed of 33.0 m/s at the top of his trajectory, determine his maximum h
nadezda [96]

Answer:

H = 6.93 m

Explanation:

given data

velocity v = 35 m/s

horizontal component Vx = 33 m/s

solution

we get here maximum height so first we get vertical component here that is express as

Vy = \sqrt{v^2- Vx^2}        .........................1

put here value

Vy = \sqrt{35^2- 33^2}

Vy = 11.66 m/s

and

now we get height

H = \frac{Vy^2}{2g}        .............................2

put here value

H = \frac{11.66^2}{2\times 9.8}

H = 6.93 m

7 0
3 years ago
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