Answer:
The covalent bond in Cl₂ is break and combine with sodium to form NaCl through ionic bond.
Explanation:
Chemical equation:
Na + Cl₂ → NaCl
Balanced chemical equation:
2Na + Cl₂ → 2NaCl
The given reaction indicate the formation of sodium chloride.
Sodium chloride is an ionic compound. It is formed by the reaction of chlorine and sodium. The type of bond in Cl₂ is covalent. Both chlorine atoms are tightly held together through sharing of electrons. When sodium chloride is formed the covalent between the chlorine atoms are break and it react with sodium . The chlorine toms thus gain the one electron from the sodium atom and became negative ion while sodium by losing its one valance electrons became positive ions. The strong electrostatic forces are develop between them and ionic bond is formed.
Answer:
drought
Explanation:
droughts are long periods without water
19 in = 1.6 ft
You know that
12 in = 1 ft
If you divide both sides by 12 in, you get the <em>conversion factor</em>: 1 = 1 ft/12 in.
If you divide both sides by 1 ft, you get the <em>conversion factor</em>: 12 in/1 ft = 1.
Both are conversion factors because they <em>both equal one</em> and <em>multiplying a measurement by one does not change its value</em>.
You choose the conversion that gives you the correct dimensions for your answer. It must have the correct dimensions <em>on top</em> (in the numerator),
Thus, to convert 19 in to ft, you use the conversion factor with “ft” on the top.
∴ Length = 19 in × (1 ft/12 in) = 1.6 ft
Answer:
1.208x10⁻³M and 392.5ppm La(NO3)3
Explanation:
The reaction that occurs is:
La2O3 + 6HNO3 → 2La(NO3)3 + 3H2O
Molarity is defined as the moles of solute (In this case, LaO3) per liter of solution. And ppm, are mg of solute per liter of solution.
To solve this question we must find the moles of La(NO3)3 produced and its mass in milligrams to find molarity and ppm:
<em>Moles La2O3 -Molar mass: 325.81g/mol-</em>
0.1968g * (1mol / 325.81g) = 6.04x10⁻⁴ moles La2O3
<em>Moles La(NO3)3:</em>
6.04x10⁻⁴ moles La2O3 * (2mol La(NO3)3 / 1mol La2O3) = 1.208x10⁻³ moles La(NO3)3
<em>Molarity:</em>
1.208x10⁻³ moles La(NO3)3 / 1L =
<h3>1.208x10⁻³M</h3>
<em>Mass La(NO3)3 -Molar mass: 324.92g/mol-</em>
1.208x10⁻³ moles La(NO3)3 * (324.92g / mol) = 0.392.5g La(NO3)3
In mg:
392.5mg La(NO3)3 / 1L =
392.5ppm La(NO3)3
