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3 years ago

Can life be found/ sustain on Mars or other planets? What conditions are required to support life on another planet?

Physics

1 answer:

Mariana [72]3 years ago

7 0

No. Oxygen( an atmosphere to contain the oxygen),water ,sunlight(energy)

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An electric dipole of dipole moment 'p' is placed in the position of stable equilibrium in a uniform field of intensity 'E'. The

larisa86 [58]

Answer:

Torque by electric dipole = pEcos thita

5 0

3 years ago

Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light.

pogonyaev

Complete Question

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light

Answer:

The diameter is $D = 0.59 \ m$

Explanation:

From the question we are told that

The best resolution is $\theta = 0.3 \ arcsecond$

The wavelength is $\lambda = 700 \ nm = 700 *10^{-9 } \ m$

Generally the

1 arcminute = > 60 arcseconds

=> x arcminute => 0.3 arcsecond

$x = \frac{0.3}{60 }$

=> $x = 0.005 \ arcminutes$

Now

60 arcminutes => 1 degree

0.005 arcminutes = > z degrees

=> $z = \frac{0.005}{60 }$

=> $z = 8.333 *10^{-5} \ degree$

Converting to radian

$\theta = z = 8.333 *10^{-5} * 0.01745 = 1.454 *10^{-6} \ radian$

Generally the resolution is mathematically represented as

$\theta = \frac{1.22 * \lambda }{ D}$

=> $D = \frac{1.22 * \lambda }{\theta }$

=> $D = \frac{1.22 * 700 *10^{-9} }{ 1.454 *10^{-6} }$

=> $D = 0.59 \ m$

4 0

3 years ago

Discuss what would happen to electrostatic force acting between two charged particles if you did the following. A. Increased the

zimovet [89]

Answer:B. Increased the amount of charge.

Explanation:

3 0

2 years ago

Snorkelers breathe through tubes that extend above the surface of the water. In prin- ciple, a snorkeler could go deeper with a

Yanka [14]

Answer:

h = 1.02 m

Explanation:

This is a fluid mechanics exercise, where the pressure is given by

P = $P_{atm}$ + ρ g h

The gauge pressure is

P - $P_{atm}$ = ρ g h

In this case the upper part of the tube we have the atmospheric pressure. and the diver can exert a pressure 10 KPa below the outside pressure, this must be the gauge pressure

$P_{m}$ = P - $P_{atm}$

$P_{m}$ = ρ g h

h = $P_{m}$ / ρ g

calculate

h = 10 103 / (1000 9.8)

h = 1.02 m

This is the depth at which man can breathe

8 0

3 years ago

Compared to the charge on a proton, the amount of charge on an electron is,

lbvjy [14]

Compared to the charge on a proton, the amount of charge on an electron is same and has the opposite sign

3 0

3 years ago