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kiruha [24]
4 years ago
8

Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his mo

torcycle after it
passes her car?
O A.
The frequency of the sound will decrease.
OB. The amplitude of the sound will increase.
0
O C. The intensity of the sound will increase.
OD. The wavelength of the sound will decrease.
0
O E.
The velocity of the sound will increase.​
Physics
2 answers:
arsen [322]4 years ago
8 0

Answer:

d

Explanation:

Alex777 [14]4 years ago
4 0
E - the velocity of the sound will increase
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PLease HURRY ITS REALLY EASY.
Leya [2.2K]

<u>[Reflection]</u>

- This occurs when light bounces off a surface (reflection is when light bounces off of something, a medium, but doesn't go through.)

- Best with a smooth surface (it is easiest for light to bounce off when the surface is smooth)

- If not for this behavior, mirrors wouldn't work (mirrors use reflection, if they did not you would not be able to see your <em>reflection</em>)

<u>[Refraction]</u>

- Light moves from one medium to another (when light moves from one medium to another, it refracts)

- Lenses in your glasses to bend light waves (refraction is all about bending light waves, so this option falls under this category)

- Microscopes and telescopes take advantage of this behavior of light (again, refraction is bending light waves. When you bend a light wave, it can make it easier to see [larger, smaller, etc] so this option is refraction)

- Light wave changes speed (light does not change speed when being reflected because it is in the same medium and just bouncing, but it refraction is changes mediums so it will bend and change speed)

[Note]

- Some of these can be figured out by knowing the definitions. For example, refraction is defined as "change in direction ... of any wave as a result of its traveling at different speeds at different points along the wave front" (Oxf/ord Languages)

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0
3 years ago
A box full of stuff was pushed for 500 N at 15 m/s2. What is the mass of the box?
stepladder [879]
F = ma
500 = m x 15
m = 33.33 kg
8 0
3 years ago
A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula
Marina86 [1]

Answer:\alpha =10.66 rad/s^2

Explanation:

Given

mass of disk m=5 kg

diameter of disc d=30 cm

Force applied F=4 N

Now this force will Produce  a  torque of magnitude

T=F\cdot r

T=4\dot 0.15

T=0.6 N-m

And Torque is given Product of moment of inertia and angular acceleration (\alpha )

T=I\cdot \alpha

Moment of inertia for Disc I= \frac{Mr^2}{2}

I=0.05625 kg-m^2

0.6=0.05625\cdot \alpha

\alpha =10.66 rad/s^2

3 0
3 years ago
You are waiting to turn left into a small parking lot. a car approaching from the opposite direction has a turn signal on. you s
TEA [102]
I think the correct answer would be A. If you are waiting to turn left into a small parking lot and a car is approaching from the opposite direction has a turn signal on, then you should wait until the other car starts its turn before making your turn. According to the general law on making a left turn, left turns should yield to the oncoming traffic. The vehicle that arrives in the intersection first would have the right of way to turn left. However, when there are two vehicles arrives at the intersection almost at the same time, then the one on the right would have the right of way.
8 0
4 years ago
A large, 68.0-kg cubical block of wood with uniform density is floating in a freshwater lake with 20.0% of its volume above the
LenaWriter [7]

Answer:

a) V = 0.085 m^3

b) m = 17 kg

Explanation:

1) Data given

mb = 68 kg (mass for the block)

20% of the block volume is floating

100-20= 80% of the block volume is submerged

2) Notation

mb= mass of the block

Vw= volume submerged

mw = mass water displaced

V= total volume for the block

3) Forces involved (part a)

For this case we have two forces the buoyant force (B), defined as the weight of water displaced acting upward and the weight acting downward (W)

Since we have an equilibrium system we can set the forces equal. By definition the buoyant force is given by :

B = (mass water displaced) g = (mw) g   (1)

The definition of density is :

\rho_w = \frac{m_w}{V_w}

If we solve for mw we got m_w = \rho_w V_w  (2)

Replacing equation (2) into equation (1) we got:

B = \rho_w V_w g (3)

On this case Vw represent the volume of water displaced = 0.8 V

If we replace the values into equation (3) we have

0.8 ρ_w V g = mg  (4)

And solving for V we have

 V =  (mg)/(0.8 ρ_w g )

We cancel the g in the numerator and the denominator we got

V = (m)/(0.8 ρ_w)

V = 68kg /(0.8 x 1000 kg/m^3) = 0.085 m^3

4) Forces involved (part b)

For this case we have bricks above the block, and we want the maximum mass for the bricks without causing  it to sink below the water surface.

We can begin finding the weight of the water displaced when the block is just about to sink (W1)

W1 = ρ_w V g

W1 = 1000 kg/m^3 x 0.085 m^3 x 9.8 m/s^2 = 833 N

After this we can calculate the weight of water displaced before putting the bricks above (W2)

W2 = 0.8 x 833 N = 666.4 N

So the difference between W1 and W2 would represent the weight that can be added with the bricks (W3)

W3 = W1 -W2 = 833-666.4 N = 166.6 N

And finding the mass fro the definition of weight we have

m3 = (166.6 N)/(9.8 m/s^2) = 17 Kg

8 0
3 years ago
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