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Rasek [7]
3 years ago
13

A motorcycle together with its Rider with 150 kg how much work is needed to set its movement at 15 metre per second.​

Physics
1 answer:
AVprozaik [17]3 years ago
5 0

Answer:

W = 16875 J

Explanation:

We have,

Mass of a motorcycle together with its rider is 150 kg

It is required to find the work is needed to set its movement at 15 metre per second. The work done is given by :

W=\dfrac{1}{2}mv^2

Plugging all the values in above formula such that :

W=\dfrac{1}{2}\times 150\times (15)^2\\\\W=16875\ J

So, the work of 16875 J is needed.

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Answer:

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3 0
3 years ago
platform diving in the olympic games takes place at two heights: 5 meters and 10 meters. What is the velocity of a diver enterin
posledela

1) Velocity: 9.9 m/s and 14 m/s

The motion of the diver is a free-fall motion, so it is a uniform accelerated motion. Choosing downward as positive direction, the final velocity can be found by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u = 0 is the initial velocity (the diver starts from rest)

a=g=9.8 m/s^2 is the acceleration of gravity

s is the displacement

For the diver jumping from 5 m, s = 5 m, so

v=\sqrt{2as}=\sqrt{2(9.8)(5)}=9.9 m/s

For the diver jumping from 10 m, s = 10 m, so

v=\sqrt{2as}=\sqrt{2(9.8)(10)}=14 m/s

2) Time: 1.01 s and 1.43 s

The time of flight of each diver can be found by using the other suvat equation

s=ut+\frac{1}{2}at^2

And since u = 0, it can be reduced to

s=\frac{1}{2}at^2

For the diver jumping from 5 m, s = 5 m, so we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(5)}{9.8}}=1.01 s

For the diver jumping from 10 m, s = 10 m, so we find

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(10)}{9.8}}=1.43 s

5 0
3 years ago
Which term defines the energy of motion?
Korvikt [17]
D kinetic energy✨
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3 years ago
The speed of an electromagnetic wave traveling in a transparent nonmagnetic substance is v = 1/ κμ0ε0 , where κ is the dielectri
vladimir1956 [14]

Answer:

v=2.24\times 10^{8}\ m/s

Explanation:

Given that,

The speed of an electromagnetic wave traveling in a transparent nonmagnetic substance is given by :

v=\dfrac{1}{\sqrt{k\mu_o\epsilon_o}}

Where

k is the dielectric constant of the substance.

v is the speed of light in water

c=\dfrac{1}{\sqrt{1.78\times 4\pi \times 10^{-7}\times 8.85\times 10^{-12}}}

v=2.24\times 10^{8}\ m/s

So, the speed of light in water is 2.24\times 10^{8}\ m/s

7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> The two main types of circuits are:
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Answer:

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