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Studentka2010 [4]
3 years ago
7

Osmotic pressure Π is given by the relation:Π = iMRTwhere i is the van’t Hoff factor, M is the concentration of solute, R is the

gas constant, and T is the temperature. The osmotic pressure of sea water is approximately 24 atm at 25°C. What is the approximate concentration of salt in sea water (approximated by NaCl with i = 2)? (Note: Use R = 0.08 L•atm/mol•K.)
Chemistry
1 answer:
lions [1.4K]3 years ago
5 0

<u>Answer:</u> The concentration of solute is 0.503 mol/L

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=icRT

where,

\pi = osmotic pressure of the solution = 24 atm

i = Van't hoff factor = 2 (for NaCl)

c = concentration of solute = ?

R = Gas constant = 0.08\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

24atm=2\times c\times 0.08\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\c=0.503mol/L

Hence, the concentration of solute is 0.503 mol/L

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Molarity for the solution is 1.48 M

Explanation:

Molarity involves the moles of solute that are contained in 1L of solution. It is a sort of concentration. The most usual.

7.73 by mass involves the mass of solute that are contained in 100 g of solution, so this one of ethylene glycol contains 7.73 g of it.

Let's determine the moles of solute

7.73 g / molar mass of ethylene glycol = moles

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84.03 mL . 1L / 1000 mL = 0.08403 L

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