1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mkey [24]
3 years ago
9

A fictional news report stated that starship Enterprise had just returned from a 10-year voyage while traveling at 0.80 c.

Physics
1 answer:
Nuetrik [128]3 years ago
4 0

Answer:

b

Explanation:

You might be interested in
An amusement park designer wants his swing to have a centripetal acceleration of 24 m/s2. If the velocity of the swing is 11 m/s
viva [34]

Answer:

<u>radius</u><u> </u><u>is</u><u> </u><u>C</u><u>:</u><u> </u><u>5</u><u>.</u><u>0</u><u> </u><u>m</u>

Explanation:

formular for centripetal acceleration:

a =  \frac{ {V}^{2} }{r}

a is acceleration

V is velocity

r is radius

24 =  \frac{ {11}^{2} }{r}  \\  \\ r =  \frac{ {11}^{2} }{24}  \\  \\ r = 5.0 \: m

5 0
3 years ago
Read 2 more answers
Genes are organized on matching pairs of _______.
natta225 [31]

Answer:

homologous chromosomes

Explanation:

6 0
3 years ago
Total lung capacity of a typical adult is approximately 5.0L. Approximately 20% of the air is oxygen, as air is 20% oxygen. At s
Tresset [83]

Answer:

n=0.03928 moles

Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles

Explanation:

The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs

Volume of oxygen in lungs =V=5*20%= 1 L=1*10^{-3} m^3

Temperature=T=37^oC=273+37=310K

Pressure at sea level = P= 1 atm=1.0125*10^5 Pa

R is universal Gas Constant =8.314 J/mol.K

Formula:

n=\frac{PV}{RT}\\n=\frac{(1.0125*10^5) *(1*10^{-3})}{(8.314)*310} \\n=0.03928 mol

Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles

8 0
4 years ago
The time constant of a simple RL circuit is defined as _______. We say that R is the resistance of the circuit and L is the indu
Gennadij [26K]

Answer:

The correct answer will be "\tau =\frac{L}{R}".

Explanation:

The time it would take again for current or electricity flows throughout the circuit including its LR modules can be connected its full steady-state condition is equal to approximately 5\tau as well as five-time constants.

It would be calculated in seconds by:

⇒  \tau=\frac{L}{R}

, where

  • R seems to be the resistor function in ohms.
  • L seems to be the inductor function in Henries.
5 0
3 years ago
An arrow of mass 0.5kg so it has 25J of kinetic energy; find the speed of the arrow v = m/s​
miss Akunina [59]

Answer:

10 m/s

Explanation:

Use the kinetic energy formula:

KE=(1/2)mv^2

I always remember it as Kevin is half-mad, and very square.

25J = (1/2)*0.5kg*(v^2)

50J = 0.5kg*(v^2)

100J = v^2

v = 10 m/s

Check it:

KE = (1/2)*0.5*(10^2)

KE = 25J

yep, it's right!

4 0
3 years ago
Other questions:
  • Which types of changes observe the law of conservation of mass?
    8·1 answer
  • Which region is located between 23.5 North and 23.5 south of the Equator
    11·2 answers
  • APAKAH VOLUME 5 KG ES SAMA DENGAN VOLUME 5KG AIR APA YG MEMBEDAKAN KEDUA ZAT TERSEBUT
    5·1 answer
  • A drag racer starts from rest and accelerates at 7.4 m/s2. How far will he travel in 2.0 seconds?
    14·1 answer
  • How does kinetic energy affect the stopping distance of a small vehicle compared to a large vehicle?
    11·1 answer
  • What displacement do I have if I travel at 10 m/s E for 10 s? A. 1 m E B. 1 m C. 100 m D. 100 m E Scalar quantities include what
    15·1 answer
  • Why do atoms bond? Describe examples of the two ways elements complete their valence
    13·2 answers
  • In order for a reaction to begin what is required
    15·2 answers
  • 1 (KE, PE) An object of mass 90 lbm is projected straight upward from the surface of the earth and reaches a height of 900 ft wh
    5·1 answer
  • How many minutes till 8:5 to 12:50<br>​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!