Answer:
16.0 g; 3.1 mol
Explanation:
(a) Mass of O atoms
Mass = 6.022 × 10^23 atoms × (2.66 × 10^-23 g/1 atom) = 16.0 g
(b) Moles of O atoms
0.050 kg = 50 g
Moles = 50 g × (1 mol/16.0 g) = 3.1 mol
Answer:
You have got the Combined Gas Equation for an Ideal Gas, which holds that
P
1
V
1
T
1
=
P
2
V
2
T
2
V
2
=
P
1
×
V
1
×
T
2
T
1
×
P
2
...
Explanation:
Answer:
4.09ₓ10²³ atoms are contained in 10g of C₃H₈
Explanation:
1 mol of C₃H₈ has 3 mol of carbon and 8 mol of hydrogen.
1 mol of C₃H₈ weighs 44 g
In 44 g of C₃H₈ we have 3 mol of C
In 10 g of C₃H₈ we'll have (10 . 3)/ 44 = 0.681 mol
1 mol of C has NA (6.02x10²³) particles
0.681 mol will have (0.681 . 6.02x10²³) = 4.09ₓ10²³ atoms
The empirical formula of c12h24o12 is a carbohydrate.
<h3>Carbohydrate</h3>
A carbohydrate is a biomolecule made up of carbon (C), hydrogen (H), and oxygen (O) atoms, often with a hydrogen-oxygen atom ratio of 2:1 (as in water), and so having the empirical formula Cm(H2O)n (where m may or may not be different from n). All molecules that meet this exact stoichiometric criterion are not, however, automatically categorized as being carbohydrates.
The term is most frequently used in biochemistry, where it is used as a synonym for saccharide, a class of compounds that includes sugars, starches, and cellulose. The four chemical categories of saccharides are monosaccharides, disaccharides, oligosaccharides, and polysaccharides. The smallest carbohydrates, monosaccharides and disaccharides, are sometimes referred to as sugars.
Learn more about carbohydrate here:
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