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Brut [27]
3 years ago
14

What force gives a 1.0 kg mass an acceleration of 7.0 m/s^2?​

Physics
2 answers:
TiliK225 [7]3 years ago
7 0

For this case we have that according to Newton's second law it is true that:

F = m * a

Where:

F: It is the force

m: It is the mass

a: It is the acceleration

According to the data we have:

m = 1.0 \ kg\\a = 7.0 \frac {m} {s ^ 2}

So, we have:

F = 1.0 \ kg * 7.0 \frac {m} {s ^ 2}\\F = 7 \ N

Thus, the applied force will be 7 Newtons.

Answer:

F = 7 \ N

weqwewe [10]3 years ago
4 0

Answer:

7N

Explanation:

From Newton's law of motion, F=ma where m is mass, a is acceleration. Since we're given mass as 1 kg and acceleration as 7 m/s2 then we substitute them directly into the above formula to get force, F.

By substitution of the above figures, F=1*7=7N

Therefore, the magnitude of force is 7N

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Which of the following statements are true?
Likurg_2 [28]

Answer:

Explanation:

(A) True: It is true.

In junction law, the current entering at a junction is equal to teh current leaving at the junction.

(B) False: It is false.

The kirchhoff's junction law is based on the conservation of charge.

(C) True: It is true.

Energy is used in the circuit.

(D) True: It is true.

It is based on the conservation of charge.

4 0
3 years ago
Why in drinking hot water, a thin-bottomed glass is taken?​
taurus [48]

Answer:

beacause it's contracts

Explanation:

when using a large bottomed glass the hot water cools that's why is good to use thin bottomed glass

6 0
3 years ago
A tennis player swings her 1000 g racket with a speed of 11 m/s. She hits a 60 g tennis ball that was approaching her at a speed
shusha [124]

Answer:

- 3.72 Ns.

9.44 m/s

Explanation:

mass of racket, M = 1000 g = 1 kg

mass of ball, m = 60 g = 0.06 kg

initial velocity of racket, U = 11 m/s

initial velocity of ball, u = 18 m/s

final velocity of ball, v = - 44 m/s

Let the final velocity of the racket is V.

(a) Momentum is defined as the product of mass and velocity of the ball.

initial momentum of the ball = m x u = 0.06 x 18 = 1.08 Ns

Final momentum of the ball = m x v = 0.06 x (- 44) = - 2.64 Ns

Change in momentum of the ball = final momentum - initial momentum

                                                        = - 2.64 - 1.08 = - 3.72 Ns

Thus, the change in momentum of the ball is - 3.72 Ns.

(b) By use of conservation of momentum

initial momentum of racket and ball = final momentum of racket and ball

1 x 11 + 0.06 x 18 =  1 x V - 0.06 x 44

12.08 = V - 2.64

V = 9.44 m/s

Thus, the final velocity of the racket afetr the impact is 9.44 m/s .

3 0
3 years ago
A 4.5cm tall object is placed 28cm in front of a spherical mirror. It is to produce a virtual image that is upright and 3.5cm ta
Ostrovityanka [42]
A- convex B- 21.77cm C- 0.01022cm D- 0.02044cm
7 0
3 years ago
As a train enters the station it slows down from 40 m/s to a 10 m/s in 5 seconds
lora16 [44]

Answer:

See the answers below.

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f}=v_{o}-a*t

where:

Vf = final velocity = 10 [m/s]

Vo = initial velocity = 40 [m/s]

t = time = 5 [s]

a = acceleration [m/s²]

Now replacing:

10=40-a*5\\40-10=a*5\\30=5*a\\a=6[m/s^{2}]

Note: The negative sign in the above equation means that the velecity is decreasing.

2)

To solve this second part we must use the following equation of kinematics.

v_{f}^{2} =v_{o}^{2} -2*a*x\\

where:

x = distance [m]

(10)^{2} =(40)^{2} -2*6*x\\100=1600-12*x\\12*x=1600-100\\12*x=1500\\x=125[m]

7 0
2 years ago
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