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CaHeK987 [17]
3 years ago
6

The figure represents a solid block of copper metal in a beaker at 30°C Which of the following best represents the particle arra

ngement as a student tips the beaker, which is kept at
30°C?
Chemistry
1 answer:
maria [59]3 years ago
6 0

Answer:

35

Explanation:

i think it is 30

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Which highly reactive gas was probably absent from the Earth's primitive atmosphere? O2 (oxygen gas) water vapor methane carbon
rosijanka [135]
Oxygen gas was most likely absent from Earth's primitive atmosphere.  The current theory is that the Earth's early atmosphere was composed of mainly carbon dioxide and methane due to the high volcanic activity.  Cyanobacteria and their use of photosynthesis was what caused earth's atmosphere to become oxygen enriched.
I hope that helps.
6 0
3 years ago
A gas sample occupies 200 mL at 760 mm Hg. What volume does the gas occupy at 400 mm Hg?
astra-53 [7]

Answer:

201.9

Explanation:

when you divided 760 with 400 yo get 19.0 the add it with 200 you get that answer

3 0
3 years ago
Consider the cell notation Cd(s) | Cd(NO3)2(aq) || AgNO3(aq) | Ag(s) with standard reduction potentials for Cd2+ and Ag+ as -0.4
MakcuM [25]

The value of the Gibbs free energy shows us that the reaction is spontaneous.

<h3>What is the Gibbs free energy?</h3>

The Gibbs free energy is a quantity that helps us to be able to determine the spontaneity of a reaction.

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Now;

△G = -nFEcell

△G = -(2 * 96500 * 1.201)

△G = -232kJ/mol

Learn more about free energy:brainly.com/question/15319033?

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8 0
1 year ago
An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it
Lera25 [3.4K]

Answer:

In full volume it contain 0.12 moles.

Explanation:

Given data:

Total volume= Vt = 2.9 L

Decreased volume= Vd = 1.2 L

Number of moles of air present in decreased volume= n = 0.049 mol

Number of moles of air in total volume= n = ?

Solution:

Formula:

Vt/ Vd = n (in total volume) /n ( decreased volume)

2.9 L / 1.2 L = X / 0.049 mol

2.42 = X / 0.049 mol

X = 2.42 × 0.049

X = 0.12 mol

6 0
3 years ago
Find if the example is correct or not and explain using CER please. Will give 5/5
ELEN [110]

The Lewis structure the student drew is incorrect. The total number of electrons in bonds and lone pairs is equal to the total number of valence electrons available, then a valid Lewis structure is produced.

The correct structure is the following:

The structure that was drawn by the student was incorrect because the total number of electrons around Oxygen were incorrect, there were 6 instead of 8, which was against the octet rule. The correct structure should have 8 electrons around each atom.

5 0
1 year ago
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