Answer:
Steven has to row at a speed to reach the same horizontal spot at the other side of the river is, V = 6 m/s
Explanation:
Given data,
The river flowing south at the rate, v = 3 m/s
To reach the other side directly across the river, he aims the raft, Ф = 30°
The speed of his raft across the river is given by the formula,
V = v / Sin Ф
= 3 / Sin 30°
= 6 m/s
Steven has to row at a speed to reach the same horizontal spot at the other side of the river is, V = 6 m/s
Answer:
6.1328 kg
60.16284 N
Explanation:
r = Radius of ball = 0.11 m
= Density of fluid =
(Assumed)
g = Acceleration due to gravity = 9.81 m/s²
m = Mass of ball
V = Volume of ball = 
The weight of the bowling ball will balance the buouyant force

The mass of the bowling ball will be 6.1328 kg
Weight will be 
Answer:
The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Explanation:
Given that,
Amplitude = 0.08190 m
Frequency = 2.29 Hz
Wavelength = 1.87 m
(a). We need to calculate the shortest transverse distance between a maximum and a minimum of the wave
Using formula of distance

Where, d = distance
A = amplitude
Put the value into the formula


Hence, The shortest transverse distance between a maximum and a minimum of the wave is 0.1638 m.
Answer:
The answer is
<h2>10 m/s²</h2>
Explanation:
To find the acceleration of an object given the force and mass we use the formula
<h3>

</h3>
From the question
mass of object = 50 kg
force = 500 N
So the acceleration is
<h3>

</h3>
We have the final answer as
<h3>10 m/s²</h3>
Hope this helps you