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marusya05 [52]
3 years ago
9

The magnetic field produced by a long straight current-carrying wire is

Physics
1 answer:
alexdok [17]3 years ago
8 0

Answer:

proportional to the current in the wire and inversely proportional to the distance from the wire.

Explanation:

The magnetic field produced by a long, straight current-carrying wire is given by:

B=\frac{\mu_0 I}{2 \pi r}

where

\mu_0 is the vacuum permeability

I is the current intensity in the wire

r is the distance from the wire

From the formula, we notice that:

- The magnitude of the magnetic field is directly proportional to I, the current

- The magnitude of the magnetic field is inversely proportional to the distance from the wire, r

Therefore, correct option is

proportional to the current in the wire and inversely proportional to the distance from the wire.

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A rotating object starts from rest at t = 0 s and has a constant angular acceleration. At a time of t = 2.5 s the object has an
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Answer:

52 rad

Explanation:

Using

Ф = ω't +1/2αt²................... Equation 1

Where Ф = angular displacement of the object, t = time, ω' = initial angular velocity, α = angular acceleration.

Since the object states from rest, ω' = 0 rad/s.

Therefore,

Ф = 1/2αt²................ Equation 2

make α the subject of the equation

α = 2Ф/t².................. Equation 3

Given: Ф = 13 rad, t = 2.5 s

Substitute into equation 3

α = 2(13)/2.5²

α = 26/2.5

α = 4.16 rad/s².

using equation 2,

Ф = 1/2αt²

Given: t = 5 s, α = 4.16 rad/s²

Substitute into equation 2

Ф = 1/2(4.16)(5²)

Ф = 52 rad.

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A car travels at a constant velocity of 20.0 meters/second for 15 seconds. What is the power of the car if the initial force app
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Work done by the force = Force x displacement. Power = work done/time = F.s/t = F.u.t/t = F.u = 95 x 20 = 1900J.                                                                                                                                                                                               {S=ut because acceleration is zero since car is moving at constant velocity}. 
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Newton's second law we can find that the correct answer is:  

 E)  It cannot be determiner whick block has more masses from the information provided

Newton's second law establishes the relationship between force, mass, and acceleration of a body. Since force and acceleration are vector quantities, their components must be added on each axis

For this problem we have two bodies, let's write Newton's second law for the body B, we assume that the body B descends

            W_b - T = m_b a

            W_b  = m_b g

            m_b - T = m_b a

Where W_b is the weight of block B, T the tension of the string, mb the mass of block b and the acceleration

Now let's find the relation for block A

let's set a datum with the x axis parallel to the ramp

           T - Wₓ = mₐ a

           sin θ = Wₓ / W

            Wₓ = Wₐ sin θ

             Wₐ = mₐ g

Where Wₓ is the component of the weight, Wₐ the weight of the body A and θ the angle of the plane

Let's write our system of equations

           m_b g - T = m_b a

           T - mₐ g sin θ = mₐ a

let's add the equations

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            a =   \frac{m_b - m_a \ sin  \ \theta}{m_b+m_a} \ g

Let's analyze this expression

  • The numerator is positive the body B descends, this occurs when

          m_b - mₐ sin θ > 0

           

  • The numerator is negative, body B rises

           m_b - mₐ  sin θ <0

We can observe that the acceleration is positive or negative depending on the relation of the masses and the angle of the plane.

In conclusion using Newton's second law we find that the correct answer is  

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learn more about Newton's second law here:

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