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Lelechka [254]
4 years ago
9

Describe a vector and how it is used​

Physics
1 answer:
Ilia_Sergeevich [38]4 years ago
8 0

Answer:

Vectors are used in science to describe anything that has both a direction and a magnitude. They are usually drawn as pointed arrows, the length of which represents the vector's magnitude.

Explanation:

They are usually drawn as pointed arrows, the length of which represents

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ball of mass 0.4 kg is attached to the end of a light stringand whirled in a vertical circle of radius R = 2.9 m abouta fixed po
Levart [38]

Answer:

6.046N

Explanation:

The net force exerted on the mass is the sum of tension force and the external force of gravity.

F_n_e_t=F_g+F_t

F_t is the tension force.F_g=9.8N/kg is the force of gravity.

F_n_e_t=ma_c=mv^2/r\\

where r is the rope's radius from the fixed point.

From the net force equation above:

F_t=F_n_e_t-F_g\\=mv^2/r-mg\\=0.4\times(8.5^2/2.9)-0.4\times9.8\\=6.046N

Hence the tension force is 6.046N

8 0
3 years ago
In thermodynamics, a closed system is a system where _____
Nady [450]
In a closed system, energy in form of heat (work) can be exchanged but not matter.

The answer to your question is C.

Hope it helped!
3 0
3 years ago
What can you use to determine whether the SATA port no which you are connecting the drive will also run at 6.0Gbps?
kolbaska11 [484]

Answer:

The answer is "use manual motherboard".

Explanation:

The motherboard is also known as the mainboard, it an electronic circuit board, that can connect with the CPU, RAM, and other networking equipment parts. It is also is known as a chipset, that differ widely in style, context, power source, height and performance (Form Factor).

All the data of the computer is stored memory, which checks into the motherboard, that the SATA port which you are connected to is still going to run at 6.0Gbps or not.

8 0
3 years ago
Which type of electricity is a one-time event, caused by unbalanced charges trying to become neutral again?
arlik [135]

Answer: yes

Explanation:

7 0
3 years ago
A 900-kg car cruising at a constant speed of 60 km/h is to accelerate to 100 km/h in 4 s. The additional power needed to achieve
kiruha [24]

To solve this problem we will apply the concepts related to power as a function of the change of energy with respect to time. But we will consider the energy in the body equivalent to kinetic energy. The change in said energy will be the difference between the two velocity data given by half of the mass. We will first convert the given units into an international system like this

Initial Velocity,

V_i = 60km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V_i = 16.6667m/s

Final Velocity,

V_f = 100km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V_f = 27.7778m/s

Now Power is defined as the change of Energy over the time,

P = \frac{E}{t}

But Energy is equal to Kinetic Energy,

P = \frac{\frac{1}{2} m\Delta v^2}{t}

P = \frac{\frac{1}{2} m(v_f^2-v_i^2)}{t}

Replacing,

P = \frac{\frac{1}{2} (900)(27.7778^2-16.6667^2)}{4}

P = 56kW

Therefore the correct answer is A.

8 0
3 years ago
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