acceleration times time falling
25*2
50 m*s^-1
Answer:
Explanation:
We put the charges in the ascending order as follows
1.53 P
3.26 P
4.66 P
5.09 P
6.39 P
where P is equal to 10⁻¹⁹
we round off given charges as follows
1.53 P → 1.6 P
3.26 P → 3.2 P
4.66 P → 4.8 P
5.09 P → 4.8 P
6.39 P → 6.4 P
We see that 2 nd to 4 th charges are integral multiples of first charge . That means these charges are supposed to be made of combination of first charge . So first charge appears to be minimum possible charge .
Hence this charge may exist on single electron.
Answer:
v(t) = 27 units
Explanation:
The function s(t) represents the position of an object at time t moving along a line such that,

and

We need to find the average velocity of the object over the interval of time [2,6]. The velocity of the object is equal to the total distance divided by time. It is given by :


v(t) = 27 units
So, the average velocity of the object is 27 units. Hence, this is the required solution.
Answer:
this is a simple application of Newton's 2nd Law: F = ma.
F = 0.023(25)
So,
F =0.575 N.
Therefore
The answer is A.
If rounded up/off.
Explanation:
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Answer:

Explanation:
We were told to calculate the speed of the ball,
Given speed of sound as 340 m
And we know that the sound of the ball hitting the pins is at 2.80 s after the ball is released from his hands.
Speed of ball = distance traveled/(time of hearing - time the sound travels).
Speed= S/t
Where S= distance traveled
t= time of hearing - time the sound travels
time=time for ball to roll+timefor sound to come back.
time of sound=16.5/340
=0.048529secs
solving for speedof ball
Then,Speed of ball = distance traveled/(time of hearing - time the sound travels).
=16.5/(2.80-0.048529) m/s = 5.997m/s
Therefore, the speed of the ball is
5.997m/s