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Anton [14]
3 years ago
12

What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters

/second in a circle with a radius of 10.0 centimeters? A. 1.82 × 102 meters/second2 B. 3.61 × 103 meters/second2 C. 5.64 × 103 meters/second2 D. 2.49 × 103 meters/second2 E. 1.18 × 103 meters/second2
Physics
1 answer:
Artist 52 [7]3 years ago
8 0

Answer:3.61(10)^{3} \frac{m}{s^{2}}

The centripetal acceleration a_{c} of an object moving in a uniform circular path is given by the following equation:

a_{c}=\frac{V^{2}}{r}

Where:

V=19m/s is the velocity

r=10cm=0.1m is the radius of the circle

a_{c}=\frac{(19m/s)^{2}}{0.1m}

a_{c}=3610m/s^{2}=3.61(10)^{3}m/s^{2}

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Which of the following is true A. If the sum of the external forces on an object is zero, then the object must be in equilibrium
yanalaym [24]

Answer:

A. If the sum of the external forces on an object is zero, then the object must be in equilibrium

Explanation:

Equilibrium, in physics, the condition of a system when neither its state of motion nor its internal energy state tends to change with time.

For a single particle, equilibrium arises if the vector sum of all forces acting upon the particle is zero.

the object is at equilibrium, then the net force acting upon the object should be 0 Newton. Thus, if all the forces are added together as vectors, then the resultant force (the vector sum) should be 0 Newton.

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3 0
3 years ago
So, RCF, or relative centrifugal force should be equal to RCF = <img src="https://tex.z-dn.net/?f=11%2C18%2Ar%2A%28RPM%2F1000%29
zysi [14]

After plugging all the data into the equation, the result of the relative centrifugal force (RCF)  is measured in terms of g.

<h3>What is relative centrifugal force?</h3>

The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.

RCF = ac/g

where;

  • ac is centripetal acceleration
  • g is acceleration due to gravity

RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2

where;

  • r is radius in cm

<h3>For example, </h3>

Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);

RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g

Thus, after plugging all the data into the equation, the result is measured in terms of g.

Learn more about relative centrifugal force here: brainly.com/question/26887699

#SPJ1

6 0
2 years ago
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