Answer:
C. 85%
Explanation:
A cylinder fitted with a piston exists in a high-pressure chamber (3 atm) with an initial volume of 1 L. If a sufficient quantity of a hydrocarbon material is combusted inside the cylinder to produce 1 kJ of energy, and if the volume of the chamber then increases to 1.5 L, what percent of the fuel's energy was lost to friction and heat?
A. 15%
B. 30%
C. 85%
D. 100%
work done by the system will be
W=PdV
p=pressure
dV=change in volume
3tam will be changed to N/m^2
3*1.01*10^5
W=3.03*10^5*(1.5-1)
convert 0.5L to m^3
5*10^-4
W=3.03*10^5*5*10^-4
W=152J
therefore
to find the percentage used
152/1000*100
15%
100%-15%
85% uf the fuel's energy was lost to friction and heat
Answer:
330.5 m
Explanation:
In this case, the object is launched horizontally at 30° with an initial velocity of 40 m/s .
The maximum height will be calculated as;

where ∝ is the angle of launch = 30°
vi= initial launch velocity = 40 m/s
g= 10 m/s²
h= 40²*sin²40° / 2*10
h={1600*0.4132 }/ 20
h= 661.1/2 = 330.5 m
Answer:
A. 12,240.
Explanation:
1,530 times 8.0 = 12,240.
hope this helped :)
Answer:
Speed=<u>Distance</u><u> </u>
Time
=<u>60</u>
12
=5m/s
Answer:

Explanation:
given,
dia of wheel = 66 cm
radius = 33 cm = 0.33 m
mass of wheel = 1.90 Kg
speed of wheel = 230 rpm
time to hold the tire = 3.10 s
Normal force = 2.7 N
coefficient of friction = 0.46
final angular speed = ?
we know
F = μ N
F = 0.46 x 2.7 = 1.242 N
torque
τ = F r
τ = 1.242 x 0.33 = 0.409 Nm
moment of inertia for wheel
I = MR²
I = 1.90 x 0.33²
I = 0.2069 kg m²
we now,
τ = I x α
α = 1.981 rad/s²
we know,



