Answer:
the measured charge will be -2 elementary charges.
Explanation:
The total amount of mass in the Sun is 2.0 x 10^30 kg, 5% of whig is hydrogen, and 13% of which becomes available for fusion. Thus, the total mass of hydrogen available for fusion over the Sun's lifetime is simply 13% of 75% of the total mass of the Sun or:
2.0 x 10^30 kg x .75 x .13
=<u> 1.95 x 10^29 kg</u>
<u />
Nuclear fusion occurs only in the core of the sun where temperature pressure and density are highest. The photosphere can be seen with visible light telescopes, the chromosphere with ultraviolet telescopes, and the corona most easily with X-ray telescopes.
The Sun is a typical star and also the closest star to the Earth. It is composed of 73% hydrogen, 25% helium, and 2% other elements. Since the gravitational pull of the sun on the earth is the centripetal force that causes the earth to move in a circular motion around the sun, we can use Newton's law of universal gravitation to find the mass of the sun without visiting it.
Learn more about The temperature here:- brainly.com/question/24746268
#SPJ4
Specific Gravity of the fluid = 1.25
Height h = 28 in
Atmospheric Pressure = 12.7 psia
Density of water = 62.4 lbm/ft^3 at 32F
Density of the Fluid = Specific Gravity of the fluid x Density of water = 1.25 x 62.4
Density of the Fluid p = 78 lbm/ft^3
Difference in pressure as we got the differential height, dP = p x g x h dP = (78 lbm/ft^3) x (32.174 ft/s^2) x (28/12 ft) [ 1 lbf / 32.174 ft/s^2] [1 ft^2 /
144in^2]
Difference in pressure = 1.26 psia
(a) Pressure in the arm that is at Higher
P = Atmospheric Pressure - Pressure difference = 12.7 - 1.26 = 11.44 psia
(b) Pressure in the tank that is at Lower
P = Atmospheric Pressure + Pressure difference = 12.7 + 1.26 = 13.96psia
Answer:
Let's assume the metal spheres are solid metal, and not charged beforehand.
The premise are similar, but the effect changes depending if you are approching from the side, between the spheres (left image) or the front (right image). Let's image the charged object is the tip of the arrow in the drawing, and it's small enough to be considered a point
In either case, the electron cloud in the spheres will be affected by the electric field generated by the charge, and gets attracted towards it (since the charge is positive and the electrons have by definition negative charge), moving according to the blue lines. For as long as the charge is in place, the "grouping" of charges on one side and the absence of charges on the other will create an electric dipole with the positive charge away from the side the arrived and the negative on the opposite end of the diameter.
The interesting part happens the moment you split the two spheres.
In the <u>left case</u> will realign based on the field lines (remember that a single charge will generate a radial field) and the moment you remove the charge the electrons are no longer drawn to one end, and will eventually re-distribute on the whole sphere, canceling the dipole.
In the <u>right case</u> instead, the fact that the spheres were touching allows the electrons in one of the sphere to migrate to the other, generating a net positive charge in the far sphere, and a net negative charge in the close one. if you separate the two spheres before removing the charge, the electrons are still "trapped" in the leftmost sphere, thus keeping it charged even after the original source is removed from the system.