All categories

3 years ago

As the energy of a wave goes up, the frequency goes

1 answer:

4 0

Salutations!

As the energy goes up, the frequency goes ------

As the energy goes up, the frequency goes up. The higher the energy goes up, it determines the frequency ( how big the wave is).

Hope I helped :D

You might be interested in

The amplitude of a standing sound wave in a long pipe closed at the left end is sketched below.

ollegr [7]

(1) The harmonic number for the mode of oscillation is 3.

(2) The pitch (frequency) of the sound is 579.55 Hz

(3) The level of the water inside the vertical pipe is 0.1 m.

<h3>The harmonic number</h3>

The harmonic number for the mode of oscillation illustrated for the closed pipe is 3.

<h3>Frequency of the wave</h3>

The pitch (frequency) of the sound is calculated from third harmonic formula;

f = 3v/4L

where;

v is speed of sound
L is length of the pipe

f = (3 x 340) / (4 x 0.44)

f = 579.55 Hz

<h3>level of the water</h3>

wave equation for first harmonic of a closed pipe is given as

f = v/(4L)

251.1 = 340/(4L)

4L = 340/251.1

4L = 1.35

L = 1.35/4

L = 0.34 m

level of water = 0.44 m - 0.34 m = 0.1 m

Thus, the level of the water inside the vertical pipe is 0.1 m.

Learn more about harmonics of closed pipes here: brainly.com/question/27248821

#SPJ1

3 0

1 year ago

Which of the following is an example of a wedge? a. a mop b. an axe c. a wheel d. a door knob

WITCHER [35]

The answer is ( b. an axe )

3 0

3 years ago

Why it is important to have exact standards of measurement

Tamiku [17]

Answer:

reference against doubt

Explanation:

exact standards of measurement are a reference point for situations in doubt , a line against which to test and observe.

6 0

3 years ago

Two loudspeakers emit identical sound waves along the x-axis. The sound at a point on the axis has maximum intensity when the sp

EleoNora [17]

The concept required to solve this problem is related to the wavelength.

The wavelength can be defined as the distance between two positive crests of a wave.

The waves are in phase, then the first distance is

$\Delta x_1 = 20cm$

And out of the phase when

$\Delta x_2 = 30cm$

Thus the wavelength is

$\Delta x_2-\Delta x_1 = \frac{\lambda}{2}$

Here,

$\lambda =$ Wavelength

If we rearrange the equation to find it, we will have

$\lambda = 2 (\Delta x_2-\Delta x_1 )$

$\lambda= 2(30-20)$

$\lambda = 20cm$

Therefore the wavelength of the sound is 20cm.

5 0

3 years ago

A 10-turn conducting loop with a radius of 3.0 cm spins at 60 revolutions per second in a magnetic field of 0.50T. The maximum e

bogdanovich [222]

Answer:

Maximum emf = 5.32 V

Explanation:

Given that,

Number of turns, N = 10

Radius of loop, r = 3 cm = 0.03 m

It made 60 revolutions per second

Magnetic field, B = 0.5 T

We need to find maximum emf generated in the loop. It is based on the concept of Faraday's law. The induced emf is given by :

$\epsilon=\dfrac{d(NBA\cos\theta)}{dt}\\\\\epsilon=NBA\dfrac{d(\cos\theta)}{dt}\\\\\epsilon=NBA\omega \sin\omega t\\\\\epsilon=NB\pi r^2\omega \sin\omega t$

For maximum emf, $\sin\omega t=1$

So,

$\epsilon=NB\pi r^2\omega \\\\\epsilon=NB\pi r^2\times 2\pi f\\\\\epsilon=10\times 0.5\times \pi (0.03)^2\times 2\pi \times 60\\\\\epsilon=5.32\ V$

So, the maximum emf generated in the loop is 5.32 V.

3 0

3 years ago