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Ksenya-84 [330]
4 years ago
11

The reaction you actually perform in this experiment has some complexity in the mechanism (Solomons p904), but you can analyze a

more simple two step version. Draw the arrow-pushing mechanism of the first step of this mechanism to form an imine. b) Draw the arrow-pushing mechanism of the second step of this mechanism to convert the imine to an amine using sodium borohydride.

Chemistry
1 answer:
kompoz [17]4 years ago
5 0

Answer:

Explanation:

Attach is the solution

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drek231 [11]

I believe that the best answer among the choices provided by the question is B. the density of freshwater remains constant as temperature decreases

6 0
4 years ago
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If a 12oz can of Soda contains 48.0g of sugar and you drink one can a day for one month (31 days), how many pounds (lb) of sugar
marishachu [46]

Answer:

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Explanation:

3 0
3 years ago
I will give brainliest!!! What is the density of a sample of chlorine gas that exerts a pressure of 4.5 atm in a 12.6 L containe
labwork [276]

Answer : The density of a sample of chlorine gas is, 12.59 g/L

Explanation :

To calculate the density of chlorine gas we are using ideal gas equation.

PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\frac{RT}{M}\\\\P=\frac{\rho RT}{M}

where,

P = pressure of chlorine gas = 4.5 atm

V = volume of chlorine gas = 12.6 L

n = number of moles of chlorine gas

w = mass of chlorine gas

R = gas constant = 0.0821 L.atm/mol.K

T = temperature of chlorine gas = 36^oC=273+36=309K

M = molar mass of chlorine gas = 71 g/mol

Now put all the given values in the above formula, we get:

P=\frac{\rho RT}{M}

4.5atm=\frac{\rho \times (0.0821L.atm/mol.K)\times (309K)}{71g/mol}

\rho=12.59g/L

Therefore, the density of a sample of chlorine gas is, 12.59 g/L

7 0
3 years ago
Which particle builds a static electric charge when it is transferred from one object to another?
murzikaleks [220]
The answer would be, "Electrons".
3 0
3 years ago
A gas has a temperature of 273.15 K and a pressure of 101.325 kPa. What can be concluded about the gas? It has reached standard
Mandarinka [93]

Explanation:

A gas has a temperature of 273.15 K and a pressure of 101.325 kPa. It can be concluded that this gas has reached standard temperature and pressure.

Standard temperature is zero degree celcius which corresponds to 273.15 degree kelvin.

Standard pressure is 760 mmHg which corresponds to 101.325 kPa.

6 0
3 years ago
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