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Degger [83]
3 years ago
11

Match the following items with their definitions. 1 . homogeneous a substance maintaining a uniform appearance throughout 2 . mi

scible a mixture consisting of visibly different substances or phases 3 . immiscible two liquids that will not mix with one another 4 . heterogeneous the ability of liquids to be mixed together
Chemistry
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer:

The answer to your question is:

Explanation:

1 . homogeneous a substance maintaining a uniform appearance throughout 2 . miscible  the ability of liquids to be mixed together

3 . immiscible two liquids that will not mix with one another

4 . heterogeneous  a mixture consisting of visibly different substances or phases

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A compound is a liquid at room temperature, dissolves in water, and the resulting solution is weakly conducting. the compound is
ZanzabumX [31]
True, for example, hydrogen peroxide (liquid):

H₂O₂ + H₂O ⇄ H₃O⁺ + HO₂⁻

HO₂⁻ + H₂O ⇄ H₃O⁺ + O₂²⁻

(the resulting solution is weakly conducting)
3 0
3 years ago
Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the pr
enot [183]

Answer:

ΔG = -8.812 kJ/mol

Explanation:

To obtain the free energy of a reaction you can use the expression:

ΔG = ΔG° + RT ln Q

<em>Where: </em>

<em>ΔG° is Standard Gibbs Free energy: -16.7kJ/mol = -16700J/mol</em>

<em>R is gas constant: 8.314472 J/molK</em>

<em>T is absolute temperature (37°C + 273.15 = 310.15K)</em>

<em>And Q is reaction quotient: 21.3</em>

<em />

Replacing in the formula:

ΔG = ΔG° + RT ln Q

ΔG = -16700J/mol + 8.314472J/molK*310.15K ln 21.3

ΔG = -8812.4J/mol

<h3>ΔG = -8.812 kJ/mol</h3>

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7 0
4 years ago
Ann drove to the store km north of her house and then drove to the library, which is 5 km south of the store. She drove a total
Vadim26 [7]
Answer : The question is incomplete, the complete question is attached in answer

To calculate the displacement by Ann's driving from north of her house to south;

we have the data as 

In north - 10 km
in south - 5 km
total - 15 km

So we can calculate the displacement, which will be,

10 - 5 = 5 km.

Hence, the displacement will be 5 km 


3 0
3 years ago
What are the empirical and molecular formulas of a hydrocarbon if combustion of 2.10 g of the compound yields 6.59 g co2 and 2.7
mariarad [96]

 The  empirical  formula    of hydrocarbon is  CH2

The  molecular formula  of the  hydrocarbon is  C6H12


    <u><em>Explanation</em></u>

Hydrocarbon  is  made up  of carbon and hydrogen


<h3><u><em> </em></u>Empirical formula  calculation</h3>

 Step 1:  find  the  moles   CO2  and  H2O

moles =mass/molar mass

moles   of CO2 =  6.59 g/ 44 g/mol = 0.15 moles

moles of H2O = 2.70 g / 18 g/mol =  0.15  moles

Step 2: Find the moles  ratio  of Co2:H2O  by diving  each mole by smallest mole(0.15)

that  is  for  CO2 = 0.15/0.15  =1

              For H2O = 0.15/0.15 =1

therefore  the mole ratio  of Co2 : H2O = 1:1  which  implies that 1 mole of Co2  and 1  mole of H2O is  formed  during combustion reaction.


From the  the law of mass conservation the number  of atoms in reactant side  must  be equal to  number of  atoms  in product side

therefore  since  there 1 atom  of C  in product side there  must be 1 atom of C  in reactant  side.

In addition  there is 2 H atom in product  side  which should be the  same  in reactant side.  

From information above the empirical formula is therefore = CH2


Molecular formula  calculation

[CH2}n= 84 g/mol

[12+ (1x2)] n = 84 g/mol

14 n =  84 g/mol

n = 6

multiply the  each subscript  in CH2  by  6

 Therefore the molecular formula = C6H12




5 0
3 years ago
Please help?! Thank you!
rjkz [21]
The answer is D, electronegativity. I hope this helps! :) Have a great day! Mark me brainliest if you'd like!
3 0
3 years ago
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